mySQL - 正確的方法來做到這一點？

我想你可以我是一個老屁，但一直是我做了mySQL（不是我自己的專家），我敢肯定有更好的方法來寫這個。希望你能幫助我。mySQL - 正確的方法來做到這一點？

SELECT 
    (SELECT MIN(bank_id) FROM bank) AS MinBank, 
    (SELECT MAX(bank_id) FROM bank) AS MaxBank, 
    (SELECT bank_id FROM bank WHERE bank_id = $UserID) AS OldBankID, 
    (SELECT bank_name FROM bank WHERE bank_id = OldBankID) AS OldBankName, 
    (SELECT bank_interest FROM bank WHERE bank_id = OldBankID) AS OldBankInterest, 
    (SELECT bank_fees FROM bank WHERE bank_id = OldBankID) AS OldBankFees, 
    (SELECT bank_pic_url FROM bank WHERE bank_id = OldBankID) AS BankPic 
    (SELECT bank_id FROM bank HAVING bank_id > (SELECT bank_id FROM users WHERE uid = $UserID) LIMIT 1) AS NewBankID, 
    (SELECT bank_name FROM bank WHERE bank_id = NewBankID) AS NewBankName, 
    (SELECT bank_interest FROM bank WHERE bank_id = NewBankID) AS NewBankInterest, 
    (SELECT bank_fees FROM bank WHERE bank_id = NewBankID) AS NewBankFees, 
    (SELECT bank_cost FROM bank WHERE bank_id = NewBankID) AS NewBankCost, 
FROM dwrel_bank LIMIT 1

基本上它是2個表：（用戶）表1 - 檢索Bank_ID（客戶的舊ID）（銀行）表2 - 獲取他們的老銀行信息和檢索他們的下一個「升級」的可用性。

它確實給我提供了我想要的信息，但是想知道我是否可以通過某種方式改善這種情況。

謝謝！

來源

2012-03-15 sgkdnay

它的混亂，在一個地方，你變老從銀行表'銀行ID在另一個你從'用戶表' – 2012-03-15 05:08:09

基本上這：從用戶的表中獲取Bank_ID。然後使用此bank_id並從銀行表中獲取信息。然而，從銀行表格中，我想要從同一張銀行表中獲得2個「重複」信息：他們當前的銀行信息和他們的下一個潛在的「升級」。 – sgkdnay 2012-03-15 05:11:43

可以更改基於oldBankId第一部分如下

select bank_id OldBankId ,bank_name OldBankName, bank_interest OldBankInterest , 
bank_fees OldBankFees, bank_pic_url as BankPic from bank 
where bank_Id =(select bank_id from bank where bank_id= $user_id)

你與newBank ID來加入這個並使用相同的語法如上

來源

2012-03-15 05:19:45

當你說join時，你的意思是UNION還是LEFT JOIN？不太確定。 – sgkdnay 2012-03-15 05:39:09

在id =（從表中選擇ID，其中id> $ userId限制爲1）' – 2012-03-15 05:44:32

希望你能夠表現出自己的方式，我有點失落嘗試它自己哈哈，在此先感謝:) – sgkdnay 2012-03-15 06:46:45

mySQL - 正確的方法來做到這一點？

回答

相關問題