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我有一個n乘2的數組'ppi',它具有整數值(帶有重複),第二個數組n'1'gid'包含來自'ppi'的唯一整數值,數組'X0'有0和1個值。下面是我想在Java的實現在Java和Matlab中給出不同結果的指數函數
MATLAB版本 -
gamma0 = 10; gamma1 = 10; beta = 20;
delta = 0;weight=10;
for i=1:length(gid)
gconn = union(ppi(find(ppi(:,1)==gid(i)),2), ppi(find(ppi(:,2)==gid(i)),1));
[a,b] = intersect(gid, gconn);
u1 = (X0(i)*weight + sum(X0(b)==1))/(weight+length(gconn));
u0 = ((1-X0(i))*weight + sum(X0(b)==0))/(weight+length(gconn));
mrfpdf(i) = exp((1-X0(i))*(gamma0-beta*u1)+X0(i)*(gamma1-beta*u0))/(exp(gamma0- beta*u1)+exp(gamma1-beta*u0));
end
Java代碼相同的實施MATLAB代碼
double[] mrfpdf = new double[X0.length];
Integer[] X = new Integer[X0.length];
// find out unique class labels in ppi
Set<Double> gid_set = new LinkedHashSet<Double>();
for (int i = 0; i < ppi.length; i++) {
for (int j = 0; j < ppi[0].length; j++) {
gid_set.add(ppi[i][j]);
}
}
System.out.println("unique gid_set: " + gid_set);
Double[] gid = gid_set.toArray(new Double[gid_set.size()]);
Arrays.sort(gid);
int gamma0 = 10, gamma1 = 10, beta = 20, delta = 0;weight=10;
for (int i = 0; i < gid.length; i++) {
Set<Double> ppi1 = new HashSet<Double>();
Set<Double> ppi2 = new HashSet<Double>();
for (int k = 0; k < ppi.length; k++) {
if (ppi[k][0] == gid[i])
ppi1.add(ppi[k][1]);
if (ppi[k][1] == gid[i])
ppi2.add(ppi[k][0]);
}
Set<Double> gconn = new HashSet<Double>(ppi1);
gconn.addAll(ppi2);
Set<Double> a = new HashSet<Double>(gid_set);
a.retainAll(gconn);
java.util.List<Double> buff = new LinkedList<Double>(gid_set);
int[] b = new int[a.size()];// get index of intersection elements in this array
int x = 0;
for (double j : a) {
for (int c = 0; c < gid.length; c++) {
if (j == gid[c]) {
b[x] = c;
x++;
}
}
}
java.util.List<Double> X0_list = new ArrayList<Double>();
for (double z : X0) {
X0_list.add(z);
}
int sum1 = 0;
for (int y : b) {
if (X0_list.get(y) == 1)
sum1++;
}
int sum2 = 0;
for (int y : b) {
if (X0_list.get(y) == 0)
sum2++;
}
u1 = (int) ((X0[i] * weight + sum1)/(weight + gconn.size()));
u0 = (int) (((1 - X0[i]) * weight + sum2)/(weight + gconn.size()));
mrfpdf[i] = (Math.exp((1 - X0[i]) * (gamma0 - beta * u1) + X0[i]* (gamma1 - beta * u0))/(Math.exp(gamma0 - beta * u1) + Math.exp(gamma1 - beta * u0)));
}// end for(int i : gid)
}
有人能告訴我爲什麼在mrfpdf值數組在Java和Matlab代碼中有所不同?在0.99 Java代碼的結果和0.5的值只,而Matlab的沒有任何值0.5
感謝
你不介意格式化?沒有人會閱讀! – Fildor
我相信你知道[每個計算機科學家應該知道什麼是浮點運算](http://docs.oracle.com/cd/E19957-01/806-3568/ncg_goldberg.html)? – Fildor