嗨我正在製作一個應用程序,它將圖片發送到服務器。使用Apache棄用函數的版本可以工作,但我不知道爲什麼我無法獲得更新的解決方案。任何人都知道這裏的錯誤在哪裏?用httpurlconnection發送圖片
最新的解決方案:它不會給logcat中的錯誤,但是當我去服務器時沒有上傳任何東西。起初,我認爲錯誤在於我如何傳遞參數,但我嘗試了幾種不同的解決方案,比如使用Uri.builder,使用HashMap和stringBuilder編碼參數的方法,傳遞字符串像這樣......並且什麼也沒有工作。我需要幫助,這是真的快把我逼瘋了
@Override
protected Void doInBackground(Void... params) {
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
image.compress(Bitmap.CompressFormat.JPEG, 100, byteArrayOutputStream);
String encodedImage = Base64.encodeToString(byteArrayOutputStream.toByteArray(), Base64.DEFAULT);
try {
byteArrayOutputStream.flush();
byteArrayOutputStream.close();
}catch (IOException e){
}
HttpURLConnection connection;
try {
String urlSt = "http://phoenixcoding.tk/SavePicture.php";
URL url = new URL(urlSt);
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
/*Uri.Builder builder = new Uri.Builder()
.appendQueryParameter("name", name)
.appendQueryParameter("image", encodedImage);
String query = builder.build().getEncodedQuery();*/
OutputStream os = connection.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write("name=example&image=" + encodedImage);
writer.flush();
writer.close();
os.close();
connection.connect();
}catch (IOException e){
e.printStackTrace();
}
return null;
}
前一種解決方案:它工作得很好
@Override
protected Void doInBackground(Void... params) {
ByteArrayOutputStream byteArrayOutputStream = new ByteArrayOutputStream();
image.compress(Bitmap.CompressFormat.JPEG, 100, byteArrayOutputStream);
String encodedImage = Base64.encodeToString(byteArrayOutputStream.toByteArray(), Base64.DEFAULT);
try {
byteArrayOutputStream.flush();
byteArrayOutputStream.close();
}catch (IOException e){
}ArrayList<NameValuePair> dataToSend = new ArrayList<NameValuePair>();
dataToSend.add(new BasicNameValuePair("name", name));
dataToSend.add(new BasicNameValuePair("image", encodedImage));
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://phoenixcoding.tk/SavePicture.php");
try{
post.setEntity(new UrlEncodedFormEntity(dataToSend));
client.execute(post);
}catch (Exception e){
e.printStackTrace();
}
return null;
}
的SavePhoto.php文件:
<?php
$name = $_POST["name"];
$image = $_POST["image"];
$decodedImage = base64_decode("$image");
file_put_contents("pictures/" . $name . ".JPG", $decodedImage);
>