C＃，檢查整數數組是否有負數

Question

我有一個數組int[] numArray。我想知道是否有任何直接的方法來檢查數組中是否有負數？

如果沒有直接的方法，即使linq會做。我對linq有點新鮮。任何人都可以建議

Answer 1

你可以使用Any：

bool containsNegative = numArray.Any(i => i < 0) 

或者

bool containsNegative = numArray.Min() < 0; 

---

編輯

int[] negativeNumbers = numArray.Where(i => i < 0).ToArray(); 

Answer 2

如果你打開使用LINQ：

var containsNegatives = numArray.Any(n => n < 0); 

或者，如果你想這樣做的「老土」的方式......你只需要循環：

var containsNegatives = false; 

foreach(var n in numArray) 
{ 
    if(n < 0) 
    { 
     containsNegatives = true; 
     break; 
    } 
} 

如果你真的想要漂亮的，你可以把它轉換成一個擴展方法：

public static class EnumerableExtensions 
{ 
    public static bool ContainsNegatives(this IEnumerable<int> numbers) 
    { 
     foreach(n in numbers) 
     { 
      if(n < 0) return true; 
     } 

     return false; 
    } 
} 

從你的代碼中調用它像：

var containsNegatives = numArray.ContainsNegatives(); 

Answer 3

var negativeExist = numArray.Any(a => a < 0); 

Answer 4

您可以使用Array.Find(T)方法來執行此任務。

public static T Find<T>(
    T[] array, 
    Predicate<T> match 
) 

例如，

using System; 
using System.Drawing; 

public class Example 
{ 
    public static void Main() 
    { 
     // Create an array of five Point structures. 
     Point[] points = { new Point(100, 200), 
      new Point(150, 250), new Point(250, 375), 
      new Point(275, 395), new Point(295, 450) }; 

     // To find the first Point structure for which X times Y 
     // is greater than 100000, pass the array and a delegate 
     // that represents the ProductGT10 method to the static 
     // Find method of the Array class. 
     Point first = Array.Find(points, ProductGT10); 

     // Note that you do not need to create the delegate 
     // explicitly, or to specify the type parameter of the 
     // generic method, because the C# compiler has enough 
     // context to determine that information for you. 

     // Display the first structure found. 
     Console.WriteLine("Found: X = {0}, Y = {1}", first.X, first.Y); 
    } 

    // This method implements the test condition for the Find 
    // method. 
    private static bool ProductGT10(Point p) 
    { 
     if (p.X * p.Y > 100000) 
     { 
      return true; 
     } 
     else 
     { 
      return false; 
     } 
    } 
} 

/* This code example produces the following output: 

Found: X = 275, Y = 395 
*/ 

Answer 5

傳統：

foreach (int number in numArray) { if (number < 0) return true; } 
return false; 

使用LINQ：

bool result = numArray.Any(x => x < 0); 

Answer 6

有點twidling版本將

public static bool AnyNegative(int[] arr){ 
    const long firstBit = 2147483648; 
    var res = false; 
    for (var i = 0; i < arr.Length && !res; i++) res = (arr[i] & firstBit) == firstBit; 
    return res; 
} 

您可以這樣調用>

int arr = {...} 
    if(arr.AnyNegative()){ 
     //do stuf if there's any negative numbers 
    } 

當然，這僅僅是一個模糊的

public static bool AnyNegative(int[] arr){ 
      var res = false; 
      for (var i = 0; i < arr.Length && !res; i++) res = arr[i] < 0; 
      return res; 
}