大的問題,這是一個有趣的挑戰!
你需要的是一個輔助表來存儲每個時間分段(在這種情況下,小時),然後加入到狀態更新重疊的地方。 LEAD()
可以抓取下一個狀態條目以檢查它是什麼時間,並且GREATEST()
和LEAST()
可以確定哪個時間適用於每個小時狀態的開始/結束。
當然,這在示例中更容易解釋。這裏是HOURS
表需要:
SQL> CREATE TABLE hours (HOUR NUMBER(2), start_m date, end_m date);
Table created.
SQL> BEGIN
2 FOR i IN 0..23 LOOP
3 INSERT INTO hours VALUES(i, to_date(lpad(i, 2, '0')||':00:00', 'HH24:MI:SS')
4 , to_date(lpad(i, 2, '0')||':59:59', 'HH24:MI:SS'));
5 END loop;
6 COMMIT;
7 END;
8/
PL/SQL procedure successfully completed.
以下是您的問題的測試數據的人口。
SQL> CREATE TABLE status_updates (NAME VARCHAR2(3), status_change_time DATE, status CHAR(1));
Table created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 18:52', 'DD-MON-RR HH24:MI:SS'), 'A');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 18:38', 'DD-MON-RR HH24:MI:SS'), 'A');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 18:33', 'DD-MON-RR HH24:MI:SS'), 'B');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 16:53', 'DD-MON-RR HH24:MI:SS'), 'A');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 16:47', 'DD-MON-RR HH24:MI:SS'), 'B');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 13:37', 'DD-MON-RR HH24:MI:SS'), 'A');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 13:33', 'DD-MON-RR HH24:MI:SS'), 'C');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 10:23', 'DD-MON-RR HH24:MI:SS'), 'C');
1 row created.
SQL> INSERT INTO status_updates VALUES ('foo',TO_DATE('15-MAY-11 10:17', 'DD-MON-RR HH24:MI:SS'), 'A');
1 row created.
SQL> commit;
Commit complete.
現在這裏是select語句來獲得所需的百分比。
SELECT t.NAME, t.HOUR, t.status, sum(round((status_end_h-start_status_h)*24*100)) per_cent
FROM (
SELECT A.NAME
, A.status
, A.status_change_time
, A.next_change_time
, b.HOUR
, greatest(status_change_time, trunc(status_change_time)+(b.start_m-trunc(b.start_m))) start_status_h
, least(next_change_time, trunc(next_change_time)+(b.end_m-trunc(b.end_m))) status_end_h
FROM (
SELECT NAME
, status
, status_change_time
, lead(status_change_time) OVER (ORDER BY NAME, status_change_time) next_change_time
FROM status_updates
) A, hours b
WHERE TO_CHAR(b.start_m, 'HH24:MI:SS') BETWEEN TO_CHAR(A.status_change_time, 'HH24:MI:SS') AND TO_CHAR(A.next_change_time, 'HH24:MI:SS')
OR TO_CHAR(b.end_m, 'HH24:MI:SS') BETWEEN TO_CHAR(A.status_change_time, 'HH24:MI:SS') AND TO_CHAR(A.next_change_time, 'HH24:MI:SS')
OR (TO_CHAR(A.status_change_time, 'HH24:MI:SS') BETWEEN TO_CHAR(b.start_m, 'HH24:MI:SS') AND TO_CHAR(b.end_m, 'HH24:MI:SS')
AND TO_CHAR(A.next_change_time, 'HH24:MI:SS') BETWEEN TO_CHAR(b.start_m, 'HH24:MI:SS') AND TO_CHAR(b.end_m, 'HH24:MI:SS'))
) t
GROUP BY t.NAME, t.HOUR, t.status
ORDER BY t.HOUR;
NAM HOUR S PER_CENT
--- ---------- - ----------
foo 10 A 10
foo 10 C 62
foo 11 C 100
foo 12 C 100
foo 13 A 38
foo 13 C 62
foo 14 A 100
foo 15 A 100
foo 16 A 90
foo 16 B 10
foo 17 A 100
NAM HOUR S PER_CENT
--- ---------- - ----------
foo 18 A 78
foo 18 B 8
13 rows selected.
好的解決方案。您不一定需要額外的表格 - 您可以在查詢中即時生成它,例如使用'從雙連接水平<= 24'技巧的選擇ROWNUM。 – 2011-05-17 01:27:09
優雅。我希望你在你工作的地方工資很高。 – 2011-05-17 19:31:35
@Jeffrey Kemp我必須對你的建議做一些閱讀。我沒有使用CONNECT BY LEVEL。聽起來不錯! – 2011-05-17 19:32:17