我試圖從json中獲取某個值。在這種情況下,我試圖獲得'isethanawake'的值,在這種情況下應該是1:如何從swift中獲取json數據中的特定值
可選([{「isethanawake」:1,「name」:「Ethan」},{「ismadisonawake」 :0,「name」:「Madison」},{「ismomawake」:0,「name」:「Mom」},{「isdadawake」:0,「name」:「爸爸」}]
代碼我已經和它不變量設置爲1
var isethanawake = 0
var ismadisonawake = 0
var ismomawake = 0
var isdadawake = 0
request2.httpBody = postString2.data(using: String.Encoding.utf8)
let task2 = URLSession.shared.dataTask(with: request2 as URLRequest){
data, response, error in
if error != nil{
print("error = \(error)")
return
}
print("response = \(response)")
let responseString = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
print("responseString = \(responseString)")
do{
let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary
if let parseJSON1 = json {
isethanawake = parseJSON1["isethanawake"] as! Int
}
if let parseJSON2 = json{
ismadisonawake = parseJSON2["ismadisonawake"] as! Int
}
if let parseJSON3 = json{
ismomawake = parseJSON3["ismomawake"] as! Int
}
if let parseJSON4 = json{
isdadawake = parseJSON4["isdadawake"] as! Int
}
print("hello" + String(isethanawake))
}catch{
print(error)
}
正是從這個PHP腳本獲取數據:
$jsonarray = array();
if(mysqli_num_rows($ethanresult)){
$returnValue1 = array("isethanawake"=> 1, "name"=> "Ethan");
array_push($jsonarray, $returnValue1);
}else{
$returnValue1 = array("isethanawake"=> 0, "name"=> "Ethan");
array_push($jsonarray, $returnValue1);
}
if(mysqli_num_rows($madisonresult)){
$returnValue2 = array("ismadisonawake"=> 1, "name"=> "Madison");
array_push($jsonarray, $returnValue2);
}else{
$returnValue2 = array("ismadisonawake"=> 0, "name"=> "Madison");
array_push($jsonarray, $returnValue2);
}
if(mysqli_num_rows($momresult)){
$returnValue3 = array("ismomawake"=> 1, "name"=> "Mom");
array_push($jsonarray, $returnValue3);
}else{
$returnValue3 = array("ismomawake"=> 0, "name"=> "Mom");
array_push($jsonarray, $returnValue3);
}
if(mysqli_num_rows($dadresult)){
$returnValue4 = array("isdadawake"=> 1, "name"=> "Dad");
array_push($jsonarray, $returnValue4);
}else{
$returnValue4 = array("isdadawake"=> 0, "name"=> "Dad");
array_push($jsonarray, $returnValue4);
}
echo json_encode($jsonarray);
}
感謝
是元組類型'(key:String,value:Any)'的值沒有成員'下標' –
如果讓ethanisawake = obj [「isethanwake」]我得到這個錯誤 –