我不斷收到這個錯誤,但是這個sql語句在mysql中可以正常工作,可能有些愚蠢,但是我在整個週末都無法工作。php mysql select語句限制
select e.*
, t.nombre
, c.compania
, c.nombre
, c.apellido
, c.ruc
, c.direccion
from envio e
inner join cliente c on e.cliente_id = c.id
inner join transporte t on t.id = e.transporte_id
limit 0, 10;
MySQL Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'limit 0, 10' at line 11
這裏的後續代碼var_dump結果:
string(263) "select e.* , t.nombre as transporte_nombre , c.compania , c.nombre , c.apellido , c.ruc , c.direccion from envio e inner join cliente c on e.cliente_id = c.id inner join transporte t on t.id = e.transporte_id limit 0, 10" MySQL Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'limit 0, 10' at line 11
這裏是我的代碼,我現在用的2班這個1是我的數據庫連接,工作正常(與其他網頁進行測試),另一個是一個返回選擇。
if(!empty($_REQUEST['page']))
$page = $_REQUEST['page'];
else
$page = "1";
$limit = 10;
if($page)
$start = ($page - 1) * $limit;
else
$start = 0;
require_once("../class/sql.php");
$db = new MySQL();
require_once("../class/envios.php");
$envios = new Envio();
var_dump($envios->BuscaEnvios("",$start,$limit));
if(is_array($conditions))
$consulta = $db->consulta($envios->BuscaEnvios($conditions,$start,$limit));
else
$consulta = $db->consulta($envios->BuscaEnvios("",$start,$limit));
if($db->num_rows($consulta) > 0)
$total_pages = $db->num_rows($consulta);
else
$total_pages = 0;
在課堂上 「Envios」:
public function BuscaEnvios($conditions, $start, $limit)
{
$sql = "select
e.*
, t.nombre as transporte_nombre
, c.compania
, c.nombre
, c.apellido
, c.ruc
, c.direccion
from envio e
inner join cliente c on e.cliente_id = c.id
inner join transporte t on t.id = e.transporte_id ";
if($conditions != "")
$sql .= ' where '. implode(' AND ', $conditions);
$sql .= " limit $start, $limit";
return $sql;
}
極限0,10基本上是說 「返回0行,開始於第10行」。我想你想要他們換個方法嗎? – GordonM
嘗試刪除分號 – knittl
@GordonM不正確,0(開始),10(行)。 – Prisoner