2014-11-21 35 views
0

我試圖獲得所有training_stages的和的days_to_complete,其中至少有一個training_tasksis_complete: => false。 (請注意,我在名爲Training的引擎正在處理)ActiveRecord具有子項匹配條件的不同記錄的總和

create_table :training_stages do |t| 
    t.references :checklist, index: true 
    t.string :name 
    t.integer :days_to_complete 

    t.timestamps 
end 

create_table :training_tasks do |t| 
    t.references :stage, index: true 
    t.string :description 
    t.boolean :is_public, default: false, null: false 
    t.boolean :is_complete, default: false, null: false 

    t.timestamps 
end 

示例數據

training_stages: 
    id checklist_id name days_to_complete created_at updated_at 
    1 1 Intake Stage 8 2014-11-21 21:03:53 2014-11-21 21:03:53 
    2 1 Document State 6 2014-11-21 21:03:53 2014-11-21 21:03:53 

training_tasks: 
    id stage_id description is_public is_complete created_at updated_at 
    1 1 Task1 1 0 2014-11-21 21:03:53 2014-11-21 21:03:53 
    2 1 Task2 0 0 2014-11-21 21:03:53 2014-11-21 21:03:53 
    3 1 Task3 1 0 2014-11-21 21:03:53 2014-11-21 21:03:53 
    4 2 Task4 1 0 2014-11-21 21:03:53 2014-11-21 21:03:53 
    5 2 Task5 0 0 2014-11-21 21:03:53 2014-11-21 21:03:53 
    6 2 Task6 1 0 2014-11-21 21:03:53 2014-11-21 21:03:53 
    7 2 Task7 0 0 2014-11-21 21:03:53 2014-11-21 21:03:53 

當我運行下面,我得到48

# Assume that stages already contains Stage.all 
stages.includes(:tasks) 
    .where(training_tasks: {is_complete: false}) 
    .sum(:days_to_complete) 

它看起來像這樣正在爲每個匹配條件的任務返回一個階段,然後將它們相加。於是我試着分組:

stages.includes(:tasks) 
    .where(training_tasks: {is_complete: false}) 
    .group("training_stages.id") 
    .sum(:days_to_complete) 

這實際上返回{1=>24, 2=>24}

如何限制總和唯一不同的階段?

回答

0

RoR中,你可以做

stages.includes(:tasks) 
.where(training_tasks: {is_complete:false}) 
.distinct.pluck(:days_to_complete).sum 

stages.includes(:tasks) 
.where(training_tasks: {is_complete:false}) 
.distinct.to_a.sum(&:days_to_complete) 
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