如何才能在加速計更改上得到通知？

Question

我工作在一個魔術八球風格的應用程序。

什麼是簡單的方法來簡單地添加一個偵聽器加速度計，當它改變了一個體面的數量（被動搖），有什麼觸發？

Answer 1

這裏是我的加速度計的代碼，我需要加速播放聲音剪輯..... 我在資源文件夾「gavel_single.wav」環......它的正常工作

I also send some references... 
    http://developer.android.com/resources/samples/AccelerometerPlay/index.html 
my code  
    import android.app.Activity; 
    import android.content.res.AssetFileDescriptor; 
    import android.hardware.Sensor; 
    import android.hardware.SensorEvent; 
    import android.hardware.SensorEventListener; 
    import android.hardware.SensorManager; 
    import android.media.MediaPlayer; 
    import android.media.MediaPlayer.OnCompletionListener; 
    import android.os.Bundle; 

    public class SensorTest extends Activity implements SensorEventListener { 
     private SensorManager sensorManager; 
     private boolean color = false; 
     private long lastUpdate; 
     private MediaPlayer mMediaplayer; 

     /** Called when the activity is first created. */ 
     @Override 
     public void onCreate(Bundle savedInstanceState) { 
      super.onCreate(savedInstanceState); 
      setContentView(R.layout.main); 
      sensorManager = (SensorManager) getSystemService(SENSOR_SERVICE); 
      sensorManager.registerListener(this, sensorManager 
        .getDefaultSensor(Sensor.TYPE_ACCELEROMETER), 
        SensorManager.SENSOR_DELAY_NORMAL); 
      lastUpdate = System.currentTimeMillis(); 
     } 

     public void onSensorChanged(SensorEvent event) { 
      if (event.sensor.getType() == Sensor.TYPE_ACCELEROMETER) { 
       float[] values = event.values; 
       // Movement 
       float x = values[0]; 
       float y = values[1]; 
       float z = values[2]; 

       float accelationSquareRoot = (x * x + y * y + z * z) 
         /(SensorManager.GRAVITY_EARTH * SensorManager.GRAVITY_EARTH); 
       long actualTime = System.currentTimeMillis(); 
       if (accelationSquareRoot >= 2) // 
       { 
        if (actualTime - lastUpdate < 200) { 
         return; 
        } 
        lastUpdate = actualTime; 

        if (color) { 

        } else { 
         try { 

          AssetFileDescriptor afd = getAssets().openFd(
            "gavel_single.wav"); 
          mMediaplayer = new MediaPlayer(); 
          mMediaplayer.setDataSource(afd.getFileDescriptor(), afd 
            .getStartOffset(), afd.getLength()); 
          afd.close(); 
          mMediaplayer.prepare(); 
          mMediaplayer.start(); 

          mMediaplayer 
            .setOnCompletionListener(new OnCompletionListener() { 

             public void onCompletion(MediaPlayer mp) { 
              mp.stop(); 
              mp.release(); 

             } 
            }); 

         } catch (Exception e) { 
          e.printStackTrace(); 
         } 

        } 

       } 

      } 

     } 

     public void onAccuracyChanged(Sensor sensor, int accuracy) { 
      // TODO Auto-generated method stub 

     } 

     @Override 
     protected void onResume() { 
      super.onResume(); 
      // register this class as a listener for the orientation and 
      // accelerometer sensors 
      sensorManager.registerListener(this, sensorManager 
        .getDefaultSensor(Sensor.TYPE_ACCELEROMETER), 
        SensorManager.SENSOR_DELAY_NORMAL); 
     } 

     @Override 
     protected void onPause() { 
      // unregister listener 
      sensorManager.unregisterListener(this); 
      super.onStop(); 
     } 

     @Override 
     protected void onDestroy() { 

      super.onDestroy(); 
      if (mMediaplayer != null) { 
       mMediaplayer.release(); 
       mMediaplayer = null; 
      } 

     } 
    } 

Answer 2

查看應用程序中的Amazed示例遊戲-for-android http://code.google.com/p/apps-for-android/

它的佈局非常整齊，易於理解。

希望這可以幫助你的方式。

m