如何使用HttpURLConnection發出oauth2請求

Question

我正在嘗試使用HttpURLConnection在Android Studio上發出Oauth2請求。但是，當我在bluestack上試用我的代碼時，應用程序崩潰了，而且我沒有發現錯誤。誰能幫我這個？

這裏是我的代碼：

package com.example.administrator.practise; 

import android.os.Bundle; 
import android.app.Activity; 
import android.view.View; 
import android.widget.Button; 
import android.widget.TextView; 
import java.io.IOException; 
import java.net.HttpURLConnection; 
import java.net.MalformedURLException; 
import java.net.URL; 

public class MainActivity extends Activity { 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 
     Button button = (Button)findViewById(R.id.auth); 
     final TextView textView1 = (TextView)findViewById(R.id.Access); 


     button.setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View v) { 
       try { 
        URL url = new URL("the url/oauth/token"); 
        HttpURLConnection connection = (HttpURLConnection)url.openConnection(); 
        connection.setRequestMethod("POST"); 
        connection.setDoInput(true); 
        connection.setDoOutput(true); 
        connection.setRequestProperty("Content-type", "application/json"); 
        connection.setRequestProperty("Accept", "application/json"); 
        connection.setRequestProperty("grant_type", "password"); 
        connection.setRequestProperty("username", "email address"); 
        connection.setRequestProperty("password", "the password"); 
        connection.setRequestProperty("client_id", "7777777"); 
        connection.setRequestProperty("client_secret", "RKdZr2tgqS7pdCCR89rcywPJqpFguaZZ9JvbKj6LMWrvuSqK8jBLMq9gqkCQcwet"); 
        connection.connect(); 
        String response = connection.getResponseMessage(); 
        textView1.setText(response); 
       } catch (MalformedURLException e) { 
        e.printStackTrace(); 
       } catch (IOException e) { 
        e.printStackTrace(); 
       } 
      } 
     }); 
    } 
} 

Answer 1

嘗試使用您的代碼AsyncTask 。

這是我的例子：

public class ThemTask extends AsyncTask<TraSua,Void,Boolean> { 
    Activity context; 

    public ThemTask(Activity context){ 
     this.context=context; 
    } 
    @Override 
    protected void onPreExecute() { 
     super.onPreExecute(); 
    } 

    @Override 
    protected void onPostExecute(Boolean aBoolean) { 
     super.onPostExecute(aBoolean); 
     String s="Thêm thất bại"; 
     if(aBoolean==true){ 
      s="Thêm thành công"; 
     } 
     Toast.makeText(context,s,Toast.LENGTH_LONG).show(); 
    } 

    @Override 
    protected void onProgressUpdate(Void... values) { 
     super.onProgressUpdate(values); 
    } 

    @Override 
    protected Boolean doInBackground(TraSua... params) { 

     try{ 
      TraSua ts=params[0]; 
      String param="?ban=" + ts.getBan() + 
        "&thucUong=" + ts.getThucUong() + 
        "&doAn=" + ts.getDoAn() + 
        "&them=" + ts.getThem(); 

      URL url=new URL("http://192.168.0.103/milktea/api/trasua"+param); 
      HttpURLConnection connection= (HttpURLConnection) url.openConnection(); 
      connection.setRequestMethod("POST"); 
      connection.setRequestProperty("content-type","application/json; charset=utf-8"); 
      InputStreamReader streamReader=new InputStreamReader(connection.getInputStream(),"UTF-8"); 
      BufferedReader bufferedReader=new BufferedReader(streamReader); 
      StringBuilder builder=new StringBuilder(); 
      String line=bufferedReader.readLine(); 
      while(line!=null){ 
       builder.append(line); 
       line=bufferedReader.readLine(); 
      } 
      String result=builder.toString(); 
      return result.contains("true"); 
     }catch(Exception e){ 
      Log.e("Loi_goi",e.toString()); 
     } 
     return false; 
    } 
}