Python的修改CSV數據

Question

我有一個文件，該文件看起來像這樣（2/3的連續的行，即隨機組合）：

String A 
String B 
String C 
<Blank Row> 
String D 
String E 
<Blank Row> 
String F 
String G 
String H 
<Blank Row> 
String I 
String J 
String K 
<Blank Row> 
String L 
String M 

我想當存在連續3行中的輸出文件以除去中間排並轉置剩餘的2行。如果只有2行，它們應該轉置。最終的結果應該是這樣的。

String A,String C 
String D,String E 
String F,String H 
String I,String K 
String L,String M 

任何指針如何做到這一點？

Answer 1

您可以使用groupby和count從itertools模塊以及list comprehension。

這個答案有點不好意思，但是要訣竅。請參閱評論以更好地理解背後的邏輯。

我假設你的投入，你是在一個名爲my_input_file文件給出了輸入和輸出文件被稱爲output_file：

from itertools import groupby, count 

# Read the file and split by the space between Value and its number 
# Leave the case where the empty string '' exists without splitting its spaces 
with open("my_input_file", 'r') as f: 
    data = (k.split() if k != '' else k for k in f.read().splitlines()) 

# Group the fields splitted, which are lists, in data 
# And separate them by the field where the string 'Blank' exists 
sub = [list(v) for _, v in groupby(data, lambda x: isinstance(x, list))] 

final = [] 
for elm in sub: 
    # if the lenght of the grouped elements is > 1 
    if len(elm) >1: 
     # Convert the number of the values into an int 
     # For further calculations 
     dd = map(lambda x: [x[0], int(x[1])], elm) 

     # Group the consecutive numbers of elem 
     for _,v in groupby(dd , lambda x,y=count(): x[1] - next(y)): 
      # If there is a consecutive numbers 
      bb = list(v) 
      if len(bb) >1: 
       # Conveert them into strings. Then, append the first and the final one to the final list 
       final.append(' '.join(map(str, bb[0])) + ',' + ' '.join(map(str, bb[-1]))) 

      # If there is'nt any consecutif numbers. Append the element to the final list 
      else: 
       final.append(" ".join(map(str, bb[0]))) 


# create the output file 
with open("output_file", 'a') as f: 
    for k in final: 
     f.write(k + '\n') 

這段代碼輸出包含一個文件：

Value 1,Value 3 
Value 4,Value 5 
Value 6,Value 8 
Value 9,Value 11 
Value 12,Value 13 

測試此代碼，並留下您的反饋，如果您有任何或可能，請報告錯誤，如果你發現任何他們。

編輯：

根據上次編輯。

如果輸入的文件是：

What Test 
Makes No Sense 
is This 

My name 
Is Sample 123 

Your Name 
is ABC 2134 

What is you 
technical question don't know 
name? 

訣竅，就是這麼簡單。你可以做這樣的事情，只有groupby利用itertools模塊：

from itertools import groupby 

with open("my_input_file", 'r') as f: 
    data = f.read().splitlines() 

final = [list(v) for _, v in groupby(data, lambda x: x != '')] 

with open("ouput_file", 'a') as f: 
    for k in final: 
     if k != ['']: 
      f.write(k[0] + ',' + k[-1] + '\n') 

而且，你的輸出文件將是：

What Test ,is This 
My name ,Is Sample 123 
Your Name ,is ABC 2134 
What is you ,name? 

Answer 2

爲了旋轉：你知道所有線路末

with open("PATH TO FILE.txt", r) as file: 
    input = file.read() 
    input.replace("\n", "") 

對於只有空格，或以確定它們的線條有一個新的生產線。到目前爲止：

with open("PATH TO FILE.txt", r) as file: 
     input = file.read() 
     if not line.strip(): 
      input.replace("\n", "") 

，你可以保持一個計數或做一個while循環，所以你計數，直到你打，只有空格行和當計數把每行一個列表或東西， 如果計算3抓住第一和第三，否則抓住兩者。請記住重置計數