我正在爲我的一個類做一個項目。教授讓我們在不使用加密庫的情況下製作RSA加密/解密程序(全部從頭開始)。所以我得到我的p,q,n,phi,e和d,一切都很好。我遇到的問題是試圖加密它。我採取每個字符的ASCII條例並使用我的e和n加密。但是,我返回的數字遠遠超出範圍,無法重新轉換爲ASCII字符。我怎樣才能把這個數字改成一個字符,並且以後還能用我的私鑰解密它?以下是我的粗略代碼:RSA加密/解密:轉換爲字符串
import random
def generatePrimes():
prime = False
while prime == False:
n = random.randint(10000, 100000) #generates random integer between 10,000 and 100,000
if n % 2 != 0: #checks if integer is divisible by 2
for x in range(3, int(n ** 0.5), 2): #starts at 3, increments by 2 to check if integer is divisible by anything
if n % x == 0:
break #if integer divides a number x and has no remainder, it isn't prime and the loop breaks
else:
prime = True #a prime number is found
return n #returns prime number
def findE(n, pn):
factor = True
while factor == True:
e = random.randint(3, 35) #creates random integer from 2 to p(n), but keeps it small for ease of use
if n % e != 0: #checks if integer is divisible by n
factor = False #if remainder is not 0, the integer isn't divisible by n. if remainer is 0, the loop restarts to choose another number
return e
def findD(e, pn):
d = pow(e, pn - 2, pn) #calculates d
return d
def encryption():
p = generatePrimes() #creates random prime number for p
q = generatePrimes() #creates random prime number for q
n = p * q #finds n by multiplying p and q
pn = (p - 1) * (q - 1) #finds p(n)
e = findE(n, pn) #creates e such that 1 < e < p(n)
d = findD(e, pn) #creates d
print('n =', n)
print('e =', e)
print('d =', d)
print('Keys have been created.')
message = input('Enter the message you wish to encrypt:')
newMessage = '' #creates new string that the encrypted message will be put into
for x in message:
x = ord(x) #converts character into ASCII reference number
x = (x ** e) % n #encrypts using rsa algorithm
x = chr(x)
newMessage += x #places new character into the encrypted string
print('Here is your encrypted message:')
print(newMessage)
def decryption():
n = int(input('Enter in a value for n:'))
d = int(input('Enter in a value for d:'))
newMessage = []
message = input('Enter the message you wish to decrypt:')
for x in message:
x = ord(x)
x = (x ** d) % n
x = chr(x)
newMessage += x
print('Here is your decrypted message:')
print(newMessage)
在附註中,編寫自己的加密算法在實際應用程序中非常糟糕。與回答這個問題無關,但我只想幫助理解程序化世界中的良好原則。 –