如何最好地捕捉OSX的睡眠和恢復事件？

Question

我想製作一個計時器，每當系統（Mac OS X Yosemite）打開時計數一次。我的想法是使用python並收聽睡眠並恢復信號，並在系統開啓時增加計數器。但是，我一直無法找到關於如何做到這一點的很多信息。

1. 以我所詳述的方式解決這個問題是否可行？
2. 有沒有更好的方法來解決這個問題？

謝謝！

Answer 1

下面是使用PyObjC（這應該是默認，或安裝的Xcode後也許可以安裝在優勝美地）的例子：

#!/usr/bin/env python 

from AppKit import NSWorkspace, NSWorkspaceWillSleepNotification, \ 
        NSWorkspaceDidWakeNotification, NSObject, \ 
        NSApplication, NSLog 

class App(NSObject): 

    def applicationDidFinishLaunching_(self, notification): 
     workspace   = NSWorkspace.sharedWorkspace() 
     notificationCenter = workspace.notificationCenter() 
     notificationCenter.addObserver_selector_name_object_(
      self, 
      self.receiveSleepNotification_, 
      NSWorkspaceWillSleepNotification, 
      None 
     ) 
     notificationCenter.addObserver_selector_name_object_(
      self, 
      self.receiveWakeNotification_, 
      NSWorkspaceDidWakeNotification, 
      None 
     ) 

    def receiveSleepNotification_(self, notification): 
     NSLog("receiveSleepNotification: %@", notification) 

    def receiveWakeNotification_(self, notification): 
     NSLog("receiveWakeNotification: %@", notification) 

if __name__ == '__main__': 
    sharedapp = NSApplication.sharedApplication() 
    app  = App.alloc().init() 
    sharedapp.setDelegate_(app) 
    sharedapp.run() 

（基於this document）