我正在建立一個按聯繫人姓氏的第一個字母分組的聯繫人列表。未捕獲TypeError:無法讀取未定義的屬性「長度」
一個succesfull AJAX請求後,將接觸被推向的addContact:
Ajax的成功:
ko.utils.arrayForEach(dataJS.contactList, function(c) {
contactsModel.addContact(c);
});
contactsModel.addContact:
//add a contact in the right spot under the right letter
contactsModel.addContact = function(newContact) {
//grab first character
var firstLetter = (newContact.lname || "").charAt(0).toUpperCase();
//if it is a number use #
if (!isNaN(firstLetter)) {
firstLetter = "#";
}
//do we already have entries for this letter
if (!this.letterIndex[firstLetter]) {
//new object to track this letter's contacts
var letterContacts = {
letter: firstLetter,
contacts: ko.observableArray([])
};
this.letterIndex[firstLetter] = letterContacts; //easy access to it
//put the numbers at the end
if (firstLetter === "#") {
this.contactsByLetter.push(letterContacts);
} else {
//add the letter in the right spot
for (var i = 0, lettersLength = this.contactsByLetter().length; i < lettersLength; i++) {
var letter = this.contactsByLetter()[i].letter;
if (letter === "#" || firstLetter < letter) {
break;
}
}
this.contactsByLetter.splice(i, 0, letterContacts);
}
}
var contacts = this.letterIndex[firstLetter].contacts;
//now we have a letter to add our contact to, but need to add it in the right spot
var newContactName = newContact.lname + " " + newContact.fname;
for (var j = 0, contactsLength = contacts().length; j < contactsLength; j++) {
var contactName = contacts()[j].lName + " " + contacts()[j].fName;
if (newContactName < contactName) {
break;
}
}
//add the contact at the right index
contacts.splice(j, 0, newContact);
}.bind(contactsModel);
觸頭JSON對象從服務器看起來像這樣:
{
"total_pages": 10,
"page": page,
"contactList": [{
"photo": "http://homepage.mac.com/millhouse/Family%20Tree/images/PersonListIcon.png",
"lname": "Bond",
"id": 241,
"fname": "James",
"email": "[email protected]"},
雖然這部作品在的jsfiddle,當我嘗試在本地,我先推過程中得到以下錯誤的addContact:
Uncaught TypeError: Cannot read property 'length' of undefined
jQuery.jQuery.extend._Deferred.deferred.resolveWithjquery-1.5.1.js:869
donejquery-1.5.1.js:6591
jQuery.ajaxTransport.send.callbackjquery-1.5.1.js:7382
想法?謝謝
在本地計算機,後'VAR接觸= this.letterIndex [firstLetter] .contacts;'做了'的console.log(聯繫人)',並確保接觸是你試圖正確的對象使用。 – jcreamer898 2012-02-23 18:56:00