HTMLJSP getServletContext()方法錯誤
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Murach's Java Servlets and JSP</title>
</head>
<body>
<%-- import packages and classes needed by the scripts --%>
<%@ page import="business.*, data.*" %>
<%
//get parameters from the request
String firstName = request.getParameter("firstName");
String lastName = request.getParameter("lastName");
String emailAddress = request.getParameter("emailAddress");
// get the real path for the EmailList.txt file
ServletContext sc = this.getServletContext();
String path = sc.getRealPath("/WEB-INF/EmailList.txt");
// use regular Java objects
User user = new User(firstName, lastName, emailAddress);
UserIO.add(user, path);
%>
<h1>Thanks for joining our email list</h1>
<p>Here is the information that you entered: </p>
<table cellspacing="5" cellpadding="5" border="1">
<tr>
<td align="right">First name:</td>
<td><%= firstName %></td>
</tr>
<tr>
<td align="right">Last name:</td>
<td><%= lastName %></td>
</tr>
<tr>
<td align="right">Email Address:</td>
<td><%= emailAddress %></td>
</tr>
</table>
<p>To enter another email address, click on the Back <br />
button in your browser or the Return button shown <br />
below.</p>
<form action="index.jsp" method="post">
<input type="submit" value="Return" />
</form>
</body>
</html>
和它給我這個錯誤頁面...
編纂的「C:\ BEA \ user_projects \域\ MYDOMAIN \ myserver.wlnotdelete \ extract \ myserver_sample01_WebContent \ jsp_servlet__display_email_entry.java'
失敗: C:\ bea \ user_projects \ domains \ mydomain。\ myserver.wlnotdelete \ extract \ mys erver_sample01_WebContent \ jsp_servlet__display_email_entry.java:140: 不能解析符號
可能 發生因在 /display_email_entry.jsp線19的錯誤:
ServletContext的SC = this.getServletContext();完整編譯器錯誤(S): C:\ BEA \ user_projects \域\ MYDOMAIN \ myserver.wlnotdelete \提取\ myserver_sample01_WebContent \ jsp_servlet__display_email_entry.java:140: 不能解析符號
符號:方法 的getServletContext( )
位置:類 爲jsp_servlet .__ display_email_entry
ServletContext的SC = this.getServletContext(); // [ /display_email_entry.jsp;線:19] ^
1錯誤
週四6月03 15點56分09秒CST 2010
任何暗示?我對JSP非常陌生,這是我第一次學習實踐...通過google.com找不到它。
是,它的工作......你能解釋一下爲什麼嗎?...... – Reigel 2010-06-03 09:40:03
有用的解釋這裏http://java.itags.org/jsp/219194/ – JoseK 2010-06-03 10:28:35
在以前的評論中的鏈接是沒有更多的可用 – ttamas 2014-09-05 14:20:25