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我試圖讓下面的代碼運行(它來自Heads First iPhone Development的書 - 第81頁),它是一個推特應用程序,當你按下按鈕發送一個簡單的短信,Twitter的:發送消息給Twitter創建一條錯誤消息
//TWITTER BLACK MAGIC
NSMutableURLRequest *theRequest=[NSMutableURLRequest
requestWithURL:[NSURL URLWithString:@"http://username:[email protected]/statuses/update.xml"]
cachePolicy:NSURLRequestUseProtocolCachePolicy
timeoutInterval: 60.0];
[theRequest setHTTPMethod:@"POST"];
[theRequest setHTTPBody:[[NSString stringWithFormat:@"status=%", themessage] dataUsingEncoding:NSASCIIStringEncoding]];
NSURLResponse* response;
NSError* error;
NSData* result = [NSURLConnection sendSynchronousRequest:theRequest returningResponse:&response error:&error];
NSLog(@"%@", [[[NSString alloc] initWithData:result encoding:NSASCIIStringEncoding] autorelease]);
//END TWITTER BLACK MAGIC
它確實在一定程度上即代碼運行,但你不能看到在Twitter上的結果 - 在resopnse我回來從Twitter在調試窗口是:
<request>/statuses/update.xml</request>
<error>Client must provide a 'status' parameter with a value.</error>
任何想法?
嗯,它真的很容易誤讀的OBJ-C,當你剛剛起步。謝謝,它現在一切正常! – Vidar 2009-11-21 22:44:54