你好,我想通過Rijaendal加密/解密一個字符串。 我根本無法弄清楚爲什麼解密爆炸。我總是以不正確的填充錯誤結束。拋出我的一件事就是我作爲HEX數組返回的加密結果。它有14個字節的長度。在我的解密函數中,相同的字節數組在從HEX轉換後最終有16個字節。Rijndael填充錯誤
任何幫助,將理解:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace rjandal
{
class Program
{
static void Main(string[] args)
{
string DataForEncrypting = "this is a test";
string key = string.Empty;
string iv = string.Empty;
using (System.Security.Cryptography.RijndaelManaged rmt = new System.Security.Cryptography.RijndaelManaged())
{
rmt.KeySize = 256;
rmt.BlockSize = 128;
rmt.Mode = System.Security.Cryptography.CipherMode.CBC;
rmt.Padding = System.Security.Cryptography.PaddingMode.ISO10126;
rmt.GenerateKey();
rmt.GenerateIV();
key = Convert.ToBase64String(rmt.Key);
iv = Convert.ToBase64String(rmt.IV);
}
string encryptedData = _encrypt(DataForEncrypting, key, iv);
string unencryptedData = _decrypt(key, iv, HexString2Ascii(encryptedData));
Console.WriteLine(unencryptedData);
Console.WriteLine(encryptedData);
Console.ReadKey();
}
private static string _encrypt(string value, string key, string initVector)
{
byte[] buffer = ASCIIEncoding.ASCII.GetBytes(value);
byte[] encBuffer;
using (System.Security.Cryptography.RijndaelManaged rmt = new System.Security.Cryptography.RijndaelManaged())
{
rmt.KeySize = 256;
rmt.BlockSize = 128;
rmt.Mode = System.Security.Cryptography.CipherMode.CBC;
rmt.Padding = System.Security.Cryptography.PaddingMode.ISO10126;
encBuffer = rmt.CreateEncryptor(Convert.FromBase64String(key),
Convert.FromBase64String(initVector)).TransformFinalBlock(buffer, 0, buffer.Length);
}
string encryptValue = ConvertToHex(ASCIIEncoding.ASCII.GetString(encBuffer));
return encryptValue;
}
private static string _decrypt(string key, string initVector, string value)
{
byte[] hexBuffer = ASCIIEncoding.ASCII.GetBytes(value);
byte[] decBuffer;
using (System.Security.Cryptography.RijndaelManaged rmt = new System.Security.Cryptography.RijndaelManaged())
{
rmt.KeySize = 256;
rmt.BlockSize = 128;
rmt.Mode = System.Security.Cryptography.CipherMode.CBC;
rmt.Padding = System.Security.Cryptography.PaddingMode.ISO10126;
decBuffer = rmt.CreateDecryptor(Convert.FromBase64String(key),
Convert.FromBase64String(initVector)).TransformFinalBlock(hexBuffer, 0, hexBuffer.Length);
}
return System.Text.ASCIIEncoding.ASCII.GetString(decBuffer);
}
private static string ConvertToHex(string asciiString)
{
string hex = "";
foreach (char c in asciiString)
{
int tmp = c;
hex += String.Format("{0:x2}", (uint)System.Convert.ToUInt32(tmp.ToString()));
}
return hex;
}
private static string HexString2Ascii(string hexString)
{
StringBuilder sb = new StringBuilder();
for (int i = 0; i <= hexString.Length - 2; i += 2)
{
sb.Append(Convert.ToString(Convert.ToChar(Int32.Parse(hexString.Substring(i, 2), System.Globalization.NumberStyles.HexNumber))));
}
return sb.ToString();
}
}
}
使用的原因是,我被要求提供IV和重點用base64和十六進制的加密結果。 – jcs 2011-02-07 20:11:00
@jcs:夠公平的;這應該爲你做的伎倆。請注意,Jon的答案在功能上會將加密值作爲base64字符串返回,而不是十六進制。 – 2011-02-07 20:17:10