提取和數據庫數據分組到一個數組

我有一個數據庫中的字段名爲「服務器」此字段在每行一個鏈接，這個領域的內容：提取和數據庫數據分組到一個數組

 
> http://www.rapidshare.com/download1 
> http://www.rapidshare.com/download2 
> http://www.rapidshare.com/download3 
> http://www.megaupload.com/download1 
> http://www.megaupload.com/download2 
> http://www.megaupload.com/download3 
> http://www.fileserve.com/download1 
> http://www.fileserve.com/download2 
> http://www.fileserve.com/download3

我想創建一個與所有的數組服務器名稱，並創建更多的數組與鏈接裏面。這是應該的：

$servers = array(
    'rapidshare'  => array(
     'link1'    => 'http://www.rapidshare.com/download1', 
     'link2'    => 'http://www.rapidshare.com/download2', 
     'link3'    => 'http://www.rapidshare.com/download3'), 
    'megaupload'  => array(
     'link1'    => 'http://www.megaupload.com/download1', 
     'link2'    => 'http://www.megaupload.com/download2', 
     'link3'    => 'http://www.megaupload.com/download3'), 
    'fileserve'   => array(
     'link1'    => 'http://www.megaupload.com/download1', 
     'link2'    => 'http://www.megaupload.com/download2', 
     'link3'    => 'http://www.megaupload.com/download3') 
);

來源

2012-01-07 user999705

你的問題是什麼？ – Borodin 2012-01-07 16:41:41

這將這樣的伎倆：（確保站點實際上是顯示$域變量了，但因爲它可能是$匹配[1] ...我不記得）

$newStructure = array(); 
foreach($links as $link) { 
    preg_match("/www\.([^\.])\.com/",$link,$matches); 
    $domain = $matches[0]; 

    $currentLength = count($newStructure[$domain]); 
    if($currentLength) { 
     $newStructure[$domain]['link'.($currentLength+1)] = $link; 
    } else { 
     $newStructure[$domain] = array('link1'=>$link); 
    } 
}

來源

2012-01-07 17:25:56 hackartist

謝謝，掩蓋相處，我也可以使用你的一些代碼！ – user999705 2012-01-08 12:44:26

當然可以。如果你喜歡它並且它對你有幫助，你可以用複選標記接受答案嗎？在堆棧溢出時，當您回答問題並被接受時，它會提高您的評分，這有助於您日後回答問題。謝謝。 – hackartist 2012-01-08 20:34:31

$server = array(
    'http://www.rapidshare.com/download1', 
    'http://www.rapidshare.com/download2', 
    'http://www.rapidshare.com/download3', 
    'http://www.megaupload.com/download1', 
    'http://www.megaupload.com/download2', 
    'http://www.megaupload.com/download3', 
    'http://www.fileserve.com/download1', 
    'http://www.fileserve.com/download2', 
    'http://www.fileserve.com/download3' 
); 

$match = array(); 
$myarray = array(); 


foreach($server as $v) { 
    // grab server name 
    preg_match('/\.(.+)\./', $v, $match); 
    $serverName = $match[1]; 

    // initialize new array if its the first link of that particular server 
    if (!isset($myarray[$serverName])) { 
     $myarray[$serverName] = array(); 
    } 

    // count server array to check how many links are there, and make next link key 
    $linkKey = 'link' . (count($myarray[$serverName]) + 1); 

    // store value 
    $myarray[$serverName][$linkKey] = $v; 
} 

print_r($myarray);

嘿，也許這會幫助你。但我沒有看到這些名稱的關鍵（link1，link2等..）的目的。這不會在分頁上工作。

來源

2012-01-07 17:29:37 kingdaemon

提取和數據庫數據分組到一個數組

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