如何在OpenFileDialog中單擊打開後讀取多個文件？

Question

我在我的代碼中設置了一個多選函數，允許我打開多個「.txt」格式的文件。這裏是問題，我打算如何通過OpenFileDialog打開所有這些選定的文件？下面的代碼和「for each」這行代碼，當我使用System :: Diagnostics :: Debug時，它只顯示來自文件的數據，而其他文件的數據丟失。我應該如何修改「for each」之後的代碼？任何人都可以提供一些建議或建議？所選文件爲1_1.txt，2_1.txt，3_1.txt。感謝您的回覆，並提前致謝。

這是我寫的代碼，

Stream^ myStream; 
OpenFileDialog^ openFileDialog1 = gcnew OpenFileDialog; 
openFileDialog1->InitialDirectory = "c:\\"; 
openFileDialog1->Title = "open captured file"; 
openFileDialog1->Filter = "CP files (*.cp)|*.cp|All files (*.*)|*.*|txt files (*.txt)|*.txt"; 
openFileDialog1->FilterIndex = 2; 
openFileDialog1->Multiselect = true; 

if (openFileDialog1->ShowDialog() == System::Windows::Forms::DialogResult::OK) 
{ 
    array<String^>^ lines = System::IO::File::ReadAllLines(openFileDialog1->FileName); 
    for each (String^ line in lines) { 
    //????? 
    System::Diagnostics::Debug::WriteLine("",line); 
    } 
} 

Answer 1

你需要看看OpenFileDialog.FileNames財產，如果你允許選擇多個文件：

if (openFileDialog1->ShowDialog() == System::Windows::Forms::DialogResult::OK) 
{ 
    for each (String^ file in openFileDialog1->FileNames) 
    { 
    array<String^>^ lines = System::IO::File::ReadAllLines(file); 
    for each (String^ line in lines) 
    { 
     System::Diagnostics::Debug::WriteLine("",line); 
    } 
    } 
} 

Answer 2

使用FileNames財產。

C＃版本（應該很容易對C適應++）：

foreach (var file in openFileDialog1.FileNames) 
{ 
    foreach (var line in File.ReadAllLines(file) 
    { 
    ... 
    } 
} 

Answer 3

使用openFileDialog1->FileNames。它返回所選

這裏 http://msdn.microsoft.com/en-us/library/system.windows.forms.openfiledialog.multiselect.aspx 讀取多個文件名及其在C＃中，但它會很容易推斷到C++。