2017-06-18 136 views
1

我試圖使我的應用程序連接到使用Retrofit 2的本地Web服務,但我總是得到這個錯誤。我確定Web服務正在響應,因爲我在Firefox中使用了一個使@GET請求和返回成功的工具,並返回了正確的JSON。改裝2錯誤:java.net.SocketTimeoutException:未能連接到10000m後的/192.168.86.1(端口8080)

在android中它甚至沒有連接。

這是我的MainActivity:

public class MainActivity extends AppCompatActivity { 

    private String API_BASE_URL="http://192.168.1.32:8080/economarket-restService/resources/androidTest/";   

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     OkHttpClient.Builder httpClient = new OkHttpClient.Builder();    

     Retrofit.Builder builder = new Retrofit.Builder() 
       .baseUrl(API_BASE_URL) 
       .addConverterFactory(GsonConverterFactory.create()); 

     Retrofit retrofit = builder.client(
       httpClient.build() 
     ).build(); 

     ContatoService contato = retrofit.create(ContatoService.class); 

     Call<Contato> repos = contato.listRespos(); //EconomarketService     

     repos.enqueue(new Callback<Contato>() { 
      @Override 
      public void onResponse(Call<Contato> call, Response<Contato> response) { 
       Contato contato = response.body(); 
       Toast.makeText(getBaseContext(), "Return" + contato.getName(), Toast.LENGTH_LONG).show(); 
       Log.d("Retorno",response.toString()); 
      } 

      @Override 
      public void onFailure(Call<Contato> call, Throwable t) { 
       Toast.makeText(getBaseContext(), "Return" + t.toString(), Toast.LENGTH_LONG).show(); 
       Log.d("Retorno",t.toString()); 
      } 
     });      
    }   
} 

我的接口:

public interface ContatoService { 
    @GET("retorna/") 
    Call<Contato> listRespos(); 
} 

模型類(Contato):

public class Contato { 

    @SerializedName("name") 
    private String name; 

    @SerializedName("phone") 
    private int phone; 

    @SerializedName("likes") 
    private int likes; 

    @SerializedName("location") 
    private Location location; 


    public String getName() { 
     return name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 

    public int getPhone() { 
     return phone; 
    } 

    public void setPhone(int phone) { 
     this.phone = phone; 
    } 

    public int getLikes() { 
     return likes; 
    } 

    public void setLikes(int likes) { 
     this.likes = likes; 
    } 



    public Location getLocation() { 
     return location; 
    } 

    public void setLocation(Location location) { 
     this.location = location; 
    } 
} 

模型類(地點):

public class Location{ 

} 
+0

使用手機瀏覽器,而不是服務器本身的Firefox工具。如果你無法連接,這是一個防火牆問題 –

+0

好的,我做到了。我在手機瀏覽器上測試過,它也正確地返回了json。 – Apolo

+0

在您的帖子標題中,「無法連接到/ 192.168.86.1」。這與您的代碼中顯示的URL不一樣 –

回答

1

問題解決了!問題是API_BASE_URL,THI URL應該只有:

"http://192.168.1.32:8080/"

和URL的其餘部分應在接口上:

@GET("economarket-restService/resources/androidTest/retorna/‌​"). 

這一切都歸結到申報的根URL_BASE中的URL和url目錄訪問必須位於接口上。

+0

'@ GET'只是附加到基本網址,所以我很驚訝這是修復 –

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