如何在yii中獲得響應爲json格式（application/json）？

Question

如何在yii中獲得響應爲json格式（application/json）？

Answer 1

在（基地）控制器創建此功能：

/** 
* Return data to browser as JSON and end application. 
* @param array $data 
*/ 
protected function renderJSON($data) 
{ 
    header('Content-type: application/json'); 
    echo CJSON::encode($data); 

    foreach (Yii::app()->log->routes as $route) { 
     if($route instanceof CWebLogRoute) { 
      $route->enabled = false; // disable any weblogroutes 
     } 
    } 
    Yii::app()->end(); 
} 

然後只需在動作結束致電：

$this->renderJSON($yourData); 

Answer 2

$this->layout=false; 
header('Content-type: application/json'); 
echo json_encode($arr); 
Yii::app()->end(); 

Answer 3

$this->layout=false; 
header('Content-type: application/json'); 
echo CJavaScript::jsonEncode($arr); 
Yii::app()->end(); 

Answer 4

Yii::app()->end() 

我覺得這個解決方案是不結束應用程序流的最好方式，因爲它使用PHP的exit()功能，女巫指執行流立即退出。是的，Yii的onEndRequest處理程序和PHP的register_shutdown_function，但它仍然過於宿命。

對我來說，更好的辦法是這樣的

public function run($actionID) 
{ 
    try 
    { 
     return parent::run($actionID); 
    } 
    catch(FinishOutputException $e) 
    { 
     return; 
    } 
} 

public function actionHello() 
{ 
    $this->layout=false; 
    header('Content-type: application/json'); 
    echo CJavaScript::jsonEncode($arr); 
    throw new FinishOutputException; 
} 

因此，應用程序流繼續即使後執行。

Answer 5

一個更簡單的方法，通過使用

echo CJSON::encode($result); 

示例代碼：

public function actionSearch(){ 
    if (Yii::app()->request->isAjaxRequest && isset($_POST['term'])) { 
      $models = Model::model()->searchNames($_POST['term']); 
      $result = array(); 
      foreach($models as $m){ 
       $result[] = array(
         'name' => $m->name, 
         'id' => $m->id, 
       ); 


      } 
      echo CJSON::encode($result); 
     } 
} 

歡呼:)

Answer 6

class JsonController extends CController { 

    protected $jsonData; 

    protected function beforeAction($action) { 
     ob_clean(); // clear output buffer to avoid rendering anything else 
     header('Content-type: application/json'); // set content type header as json 
     return parent::beforeAction($action); 
    } 

    protected function afterAction($action) { 
     parent::afterAction($action); 
     exit(json_encode($this->jsonData)); // exit with rendering json data 
    } 

} 

class ApiController extends JsonController { 

    public function actionIndex() { 
     $this->jsonData = array('test'); 
    } 

} 

Answer 7

在控制器的行動，要呈現JSON數據，例如：actionJson（）

public function actionJson(){ 
    $this->layout=false; 
    header('Content-type: application/json'); 
    echo CJSON::encode($data); 
    Yii::app()->end(); // equal to die() or exit() function 
} 

查看更多Yii API

Answer 8

對於Yii2控制器內：

public function actionSomeAjax() { 
    $returnData = ['someData' => 'I am data', 'someAnotherData' => 'I am another data']; 

    $response = Yii::$app->response; 
    $response->format = \yii\web\Response::FORMAT_JSON; 
    $response->data = $returnData; 

    return $response; 
}