我有一個存儲在文本文件中的文件列表。我一行一行地讀取文件,並將它們存儲在一個字符串數組中。文件列表如下所示:如何從文本文件中讀取文件名列表並在C++中打開它們?
04_02_1310.csv
04_03_1350.csv
04_04_0421.csv
04_05_0447.csv
等等。讓我們把我的字符串數組
filelist[i]
假設我想在列表中打開的第一個文件:
inputFile.open(filelist[0].c_str()); // This cannot open file
文件無法打開。如果我用引號將文件名,一切順利罰款:
inputFile.open("04_02_1310.csv"); // This works perfectly
如果我打印的文件列表中的內容[I],然後正常工作,以及:
cout << filelist[0] << endl; // This outputs 04_02_1310.csv on screen.
有人可以告訴我上面的方法有什麼問題?這使我在過去的2天內瘋狂,而我正在手動輸入所有內容,以便完成它(100個以上的文件)。
我也願意以其他任何方式來完成這個簡單的任務。
謝謝!
編輯:再次
Data file could not be opened
感謝:我添加的代碼的相關部分,如果你想看看它是如何實現的:
#include <cstdlib>
#include <iostream>
#include <time.h>
#include <string>
#include <sstream>
#include <fstream>
#include <vector>
#include <algorithm>
#include <iterator>
using namespace std;
//Declarations for I/O files
ifstream inputFile;
//Declare other variables (forgot to add these in my previous EDIT, sorry)
int number_of_files;
string line;
string *filelist = NULL;
//Open file list and count number of files
inputFile.clear();
inputFile.open("filelist.txt", ios::in);
//exit and prompt error message if file could not be opened
if (!inputFile){
cerr << "File list could not be opened" << endl;
exit(1);
}// end if
// count number of lines in the data file and prompt on screen
number_of_files = 0;
while (getline(inputFile, line))
number_of_files++;
cout << "Number of files to be analyzed: " << number_of_files << endl;
filelist = new string[number_of_files];
inputFile.close();
//Re-open file list and store filenames in a string array
inputFile.clear();
inputFile.open("filelist.txt", ios::in);
//exit and prompt error message if file could not be opened
if (!inputFile){
cerr << "File list could not be opened" << endl;
exit(1);
}// end if
// store filenames
i = 0;
while (getline(inputFile, line)){
filelist[i] = line;
//cout << filelist[i] << endl;
i = i + 1;
}
inputFile.close();
//open first file in the list, I deleted the loop to focus on the first element for now
inputFile.clear();
inputFile.open(filelist[0].c_str(), ios::in);
//exit and prompt error message if file could not be opened
if (!inputFile){
cerr << "Data file could not be opened" << endl;
exit(1);
}// end if
的輸出!
什麼'COUT <<文件列表[0] .c_str()<< ENDL;'或'COUT <<文件列表[I] .c_str()<< ENDL;'? – 2012-07-13 15:58:50
你可以發佈循環? – pearcoding 2012-07-13 15:59:22
Luchian'cout << filelist [0] .c_str()<< endl;'給出了與'cout << filelist [0] << endl;'完全相同的結果。這使我瘋狂:) – marillion 2012-07-13 16:05:26