Python 3：將2個元素列表到字典

Question

Python3 OMG，對於可能以這種或那種方式經常重複提出的問題感到抱歉。對我來說，操縱名單一直就像一個黑匣子的頭痛，我一直在爭鬥一個小時，沒有結果。

我有形式的列表：

[('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 

我想變成一個可迭代的字典這個（是我，然後批量插入作爲使用pymongo文件），因此它看起來像這樣：

new_posts = [{"sender": "John", 
       "email": "first@email.com"}, 
       {"sender": "John", 
       "email": "second@email.com"}, 
       {"sender": "Jack", 
       "email": "third@email.com"}] 

這將如何以易於閱讀和有效的方式實現？

Answer 1

您可以嘗試

>>> a = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 
>>> [dict([('sender', x[0]), ('email',x[1])]) for x in a] 
[{'sender': 'John', 'email': 'first@email.com'}, {'sender': 'John', 'email': 'second@email.com'}, {'sender': 'Jack', 'email': 'third@email.com'}] 

這將轉換列表與dict

Answer 2

your_list = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 
your_result = [{'sender': sender, 'email': email} for sender, email in your_list] 

Answer 3

data = [('John', 'first@email.com'), ('John', 'second@email.com'), ('Jack', 'third@email.com')] 
new_posts = [] 
for i in range(len(data)): 
    new_post = {} 
    new_post["sender"] = data[i][0] 
    new_post["email"] = data[i][1] 
    new_posts.append(new_post) 

解決它的另一種方式..