選擇查詢以獲得SQL Server中的總記錄數

Question

嗨，我有一個表與狀態列。如何使用SQL獲取記錄總數，帶有傳遞狀態的記錄總數和帶有失敗狀態的記錄總數？

Answer 1

我會寫類似

select 
Count(*) as TotalRecords, 
Sum(case where status = 'Pass' then 1 else 0 end) as PassRecords, 
Sum(case where status = 'Fail' then 1 else 0 end) as FaileRecords 
from Table 

Answer 2

怎麼是這樣的：

SELECT Status, COUNT(*) 
FROM dbo.YourTable 
GROUP BY Status WITH ROLLUP 

這會工作，如果這兩個狀態（及格，不及格）是唯一的狀態（否則你需要一個WHERE Status IN ('fail', 'pass')條件還） - 和WITH ROLLUP也將給你行的總數（以輸出與Status = NULL）所有狀態

Answer 3

您可以用case語句和聚合做到這一點：

select count(*), sum(case when status = 'pass' then 1 else 0 end) as pass, 
     sum(case when status = 'fail' then 1 else 0 end) as fail 
from t 

Answer 4

一對夫婦的其他替代品（SQL服務器2008+）查詢：

DECLARE @foo TABLE([status] CHAR(4)); 

INSERT @foo SELECT 'pass' 
UNION ALL SELECT 'pass' 
UNION ALL SELECT 'fail'; 

-- option #1: 

SELECT [status], c = COUNT(*) 
FROM @foo 
GROUP BY GROUPING SETS(([status]),()); 

-- option #2: 

SELECT [status], c = COUNT(*) 
FROM @foo 
GROUP BY [status] 
UNION ALL 
SELECT NULL, COUNT(*) OVER() FROM @foo;