我有一個html表單,應該通過jquery ajax將數據提交給php文件。代碼可以在下面看到。我遇到的問題是,單擊提交時,ajax似乎沒有將數據傳遞給php,因爲done()函數下的console.log返回$ data對象,顯示所有字段都爲空(即當字段爲空時返回錯誤消息)。我根本得不到問題所在。當我提交表單而不使用ajax,即禁用整個$('form')。submit(...)塊時,成功消息返回true。阿賈克斯塊始終返回false使用jquery ajax將數據傳遞給php的問題
<form id="sds_contact_form" class="sds_form" action="form_submit.php" method="post">
<!-- name -->
<div class="sds_input_group sds_half_field">
<label for="sds_sender_name">full name*</label>
<input id="sds_sender_name" name="sds_customer" type="text" placeholder="eg John smith" required />
<span id="sds_customername_error" class="sds_error_span"></span>
</div>
<!-- email address -->
<div class="sds_input_group sds_half_field">
<label for="sds_sender_email">email*</label>
<input id="sds_sender_email" name="sds_form_email" type="email" placeholder="eg [email protected]" required />
<span id="sds_email_error" class="sds_error_span"></span>
</div>
<!-- subject -->
<div class="sds_input_group">
<label for="sds_email_subject">subject*</label>
<input id="sds_email_subject" name="sds_form_subject" type="text" placeholder="e.g need an app designed" required />
<span id="sds_subject_error" class="sds_error_span"></span>
</div>
<!--enquiry -->
<div class="sds_input_group">
<label for="sds_sender_enquiry">enquiry*</label>
<span id="sds_enquiry_error" class="sds_error_span"></span>
<textarea id="sds_sender_enquiry" name="sds_form_enquiry" placeholder="enter details here" rows="15" required></textarea>
</div>
<!-- submit button -->
<button name="sds_submit_enquiry" type="submit" class="sds_form_button sds_button">send</button>
</form>
這是jQuery代碼
//form data submission
$('form').submit(function(event){
var form_data = {
'customer_name' : $('#sds_sender_name').val(),
'customer_email' : $('#sds_sender_email').val(),
'email_subject': $('#sds_email_subject').val(),
'enquiry': $('#sds_sender_enquiry').val()
};
console.log(form_data);
$.ajax({
url :'form_submit.php',
type:'POST',
data:form_data,
dataType:'json',
}).done(function(data){
console.log(data);
}).fail(function(xhr, ajaxOptions, thrownError){
console.log("ERROR:" + xhr.responseText+" - "+thrownError);
});
event.preventDefault();
});
這是PHP代碼中form_submit.php
<?php
$data = array();
$errors = array();
//get form data
$customer_name = $_POST['sds_customer'];
$customer_email = $_POST['sds_form_email'];
$email_subject = $_POST['sds_form_subject'];
$enquiry = $_POST['sds_form_enquiry'];
//validate name
if(empty($customer_name)){
$errors['customer_name'] = 'name is required';
}
//validate email
if(empty($customer_email)){
$errors['customer_email'] = 'email is required';
}else{
if(!filter_var($customer_email,FILTER_VALIDATE_EMAIL)){
$errors['customer_email'] = 'email provided is invalid';
}
$customer_email = filter_var($customer_email,FILTER_SANITIZE_EMAIL);
}
//validate form subject
if(empty($email_subject)){
$errors['email_subject'] = 'subject is required';
}else{
$email_subject = filter_var($email_subject,FILTER_SANITIZE_STRING);
}
//validate form comments
if(empty($enquiry)){
$errors['enquiry'] = 'please enter your enquiry';
}else{
$enquiry = filter_var($enquiry,FILTER_SANITIZE_STRING);
}
if(!empty($errors)){
$data['success'] = false;
$data['errors'] = $errors;
}else{
$data['success'] = true;
$data['message'] = "Your email has been sucessfully sent. Thank you for your enquiry. Exepect a response soon!";
//further data processing here....
}
echo json_encode($data);
?>
中完成的部分,你應該使用JSON.parse(數據);因爲你是從php – Jigar7521
@ Jigar7521傳遞json解碼不,他不應該這樣做。如果AJAX的dataType定義爲JSON,則不需要JSON.parse。 –