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我一直在考慮一個CSV文件中的數據的列是一個JSON字符串看起來像當加載到大熊貓如下:如何JSON字符串的大熊貓列轉換成一個新的數據幀
df.registered_office.head()
3 {u"country": u"United Kingdom", u"region": None, u"postal_code": u"ST6 3HL", u"street_address": u"Martin Leake House Waterloo Road\nCobridge", u"locality": u"Stoke On Trent"}
5 {u"country": u"England", u"region": None, u"postal_code": u"BS32 4JY", u"street_address": u"Woodlands Grange Woodlands Lane\nBradley Stoke", u"locality": u"Bristol"}
7 {u"country": u"United Kingdom", u"region": u"Staffordshire", u"postal_code": u"ST6 8JD", u"street_address": u"136 Knypersley Road\nNorton", u"locality": u"Stoke On Trent"}
8 {u"country": u"United Kingdom", u"region": u"Staffordshire", u"postal_code": u"ST9 9HQ", u"street_address": u"Ashlands\n253 Leek Road, Endon", u"locality": u"Stoke On Trent"}
9 {u"country": u"United Kingdom", u"region": None, u"postal_code": u"ST1 5TA", u"street_address": u"C/O Kpmg Festival Way\nStoke On Trent", u"locality": None}
Name: registered_address, dtype: object
根據各種不同的密鑰,將這一列轉換爲新的數據框或新列的最蟒蛇方式是什麼?
謝謝您的迅速反應。它幾乎可以工作,但它將字符串中的單個字符拆分爲列,而不是鍵。 – elksie5000
所以你需要轉置? 'print(pd.DataFrame.from_records(df.registered_office.values.tolist())。T)'? – jezrael
你的輸出是不同的? – jezrael