我想推動JSON編碼形式我的數據庫選擇到chart.js數據集,但即時通訊不知道如何去解決它,而沒有過度工程。推動JSON編碼的PHP到chart.js
下面是一個簡單的選擇,從它的追溯表分數:
if($teamData == 0){
$allTeams = 'All';
} else{
$sql = "SELECT * FROM compScore WHERE memberId = 1";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$jsonScores = json_encode($row, JSON_PRETTY_PRINT);
}
}
}
header('Content-type: application/json');
echo $jsonScores;
的這個輸出是:
{ "id": "1", "score1": "2", "score2": "3", "score3": "5", "score4": "4", "score5": "3", "score6": "2", "score7": "1", "score8": "3", "memberId": "1" }
我有一個問題,即只取1分的記錄,我也想排除該字段memberId
更何況我如何將該結果推送到:
datasets : [
{
fillColor: "rgba(102,45,145,.1)",
strokeColor: "rgba(102,45,145,1)",
pointColor : "rgba(220,220,220,1)",
pointStrokeColor : "#fff",
data : [] // HERE IS WHERE THE DATA NEEDS TO GO
}
首先從陣列中刪除不必要的元素。請參閱此鏈接:http://stackoverflow.com/questions/4466159/delete-element-from-multidimensional-array-based-on-value –
之後,將其編碼爲json格式並傳入js庫部分。 –
@prakashtank即時通訊不知道如何將它傳遞到js庫,這就是我有點卡住 – PhpDude