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我的問題有點傻,但我不知道該怎麼做。我創建使用標準結構的標準flexigrid:如何用代碼點火器中的另一個控制器的傳入變量創建flexigrid?
//ver lib
/*
* 0 - display name
* 1 - width
* 2 - sortable
* 3 - align
* 4 - searchable (2 -> yes and default, 1 -> yes, 0 -> no.)
*/
$colModel['users.id'] = array('id',40,TRUE,'center',1);
$colModel['users.first_name'] = array('first_name',80,TRUE,'center',0);
$colModel['users.last_name'] = array('last_name',180,TRUE,'left',1);
$colModel['users.email'] = array('email',120,TRUE,'left',0);
$colModel['users.username'] = array('username',130, TRUE,'left',0);
$colModel['users.activation_code'] = array('activation_code',80, FALSE, 'right',0);
$colModel['users.activated'] = array('activated',80, FALSE, 'right',0);
$colModel['lists'] = array('Lists',90, FALSE, 'right',0);
/*
* Aditional Parameters
*/
$gridParams = array(
'width' => 'auto',
'height' => 400,
'rp' => 15,
'rpOptions' => '[10,15,20,25,40]',
'pagestat' => 'Displaying: {from} to {to} of {total} items.',
'blockOpacity' => 0.5,
'title' => 'Hello',
'showTableToggleBtn' => true
);
/*
* 0 - display name
* 1 - bclass
* 2 - onpress
*/
$buttons[] = array('Delete','delete','test');
$buttons[] = array('separator');
$buttons[] = array('Select All','add','test');
$buttons[] = array('DeSelect All','delete','test');
$buttons[] = array('separator');
//Build js
//View helpers/flexigrid_helper.php for more information about the params on this function
$grid_js = build_grid_js('flex1',site_url("admin/users/list_users"),$colModel,'users.first_name','asc',$gridParams,$buttons);
$data['js_grid'] = $grid_js;
$this->load->view('admin_panel/admin_content', $data);
現在我的問題是:是否有可能創建第三URI段參數的flexigrid?例如,我想顯示一個列表,該列表由用戶創建並執行,我需要他的ID。我可以輕鬆地在同一個控制器中執行該操作,但我想將它傳遞給不同的控制器,並在那裏創建新的flexigrid表單。所以在'index()'方法我可以有,例如$ get_id變量從不同的控制器傳遞?喜歡這個?
$grid_js = build_grid_js('flex1',site_url("admin/admin_lists/display_show_list/".$get_id),$colModel,'name','asc',$gridParams,$buttons);
我希望我解釋得很好。有人可以給我一些幫助嗎?大多讚賞任何提示!
謝謝Yman的回覆。很好的隊友! – Pavel 2010-09-16 07:00:33
沒有問題!別客氣 – Yman 2010-09-16 15:06:40