不同意見共享Django聯繫表

Question

我可以發誓這是過去工作，但顯然我沒有測試，因爲我應該有。我有一個表格，允許用戶請求關於特定房地產列表的信息。有四（4）個單獨的視圖，其中一個顯示所有，另三個簡單地按屬性過濾列表，即租賃，僅限於房地產等。

表單的工作方式應該像它應該在視圖中列出對象.all（）和我以爲我可以在我的其他視圖中調用form_class，但是當我在被過濾的頁面上時，表單不起作用...瀏覽器中沒有錯誤消息或任何東西，電子郵件只是從來沒有到達我們的收件箱。

如果你可以看看我的觀點並提供一些反饋，我將非常感激，請讓我知道如果你需要看到任何其他的東西。謝謝。

from django.template.loader import get_template 
from django.core.mail import EmailMessage 
from django.template import Context 
from django.shortcuts import render, redirect 
from .models import Listing 
from .forms import ContactForm 


def listing_list(request): 
    listings = Listing.objects.all().order_by('listing_order') 
    form_class = ContactForm 

    if request.method == 'POST': 
     form = form_class(data=request.POST) 

     if form.is_valid(): 
      contact_name = request.POST.get('contact_name', '') 
      contact_phone = request.POST.get('contact_phone', '') 
      contact_email = request.POST.get('contact_email', '') 
      contact_listing = request.POST.get('contact_listing', '') 
      form_content = request.POST.get('content', '') 

      # Email the profile with the 
      # contact information 
      template = get_template('contact_template.txt') 
      context = Context({ 
       'contact_name': contact_name, 
       'contact_phone': contact_phone, 
       'contact_email': contact_email, 
       'contact_listing': contact_listing, 
       'form_content': form_content, 
      }) 
      content = template.render(context) 

      email = EmailMessage("Form Submission from Listings Page", content, contact_email, 
           ['to1@emailaddress.com', 'to2@emailaddress.com'], ['bcc@emailaddress.com']) 

      email.send() 

      return redirect('listing_list') 
    return render(request, 'listing/listing_list.html', {'listings': listings, 'form': form_class}) 


def full_service(request): 
    listings = Listing.objects.filter(location_type='FULL_SERVICE').order_by('listing_order') 
    form_class = ContactForm 
    return render(request, 'listing/listing_list.html', {'listings': listings, 'form': form_class}) 


def quick_serve(request): 
    listings = Listing.objects.filter(location_type='QUICK_SERVE').order_by('listing_order') 
    form_class = ContactForm 
    return render(request, 'listing/listing_list.html', {'listings': listings, 'form': form_class}) 


def with_real(request): 
    listings = Listing.objects.filter(location_type='WITH_REAL').order_by('listing_order') 
    form_class = ContactForm 
    return render(request, 'listing/listing_list.html', {'listings': listings, 'form': form_class}) 

Answer 1

Class-based views（和someneat Django的shortcuts）救援：

from django.core.mail import send_mail 
from django.views import generic 
from django.template import render_to_string 


class ContactFormView(generic.FormView): 
    form_class = ContactForm 
    template_name = 'listing/listing_list.html' 
    success_url = 'listings' 
    location_type = None 

    def get_context_data(self, **kwargs): 
     context = super(ContactFormView, self).get_context_data(**kwargs) 
     context['listings'] = (Listing.objects 
           .filter(location_type=self.location_type) 
           .order_by('listing_order')) 
     return context 

    def form_valid(self, form): 
     message = render_to_string('contact_template.txt', form.cleaned_data) 
     send_mail('Form Submission from Listings Page', message, 
        form.cleaned_data['contact_email']) 
     return super(ContactFormView, self).form_valid(form) 


class FullService(ContactFormView): 
    location_type='FULL_SERVICE' 


class QuickServe(ContactFormView): 
    location_type='QUICK_SERVE'