CKEditor從選擇中刪除選項

Question

我想從CKEditor的'鏈接'選項卡上的linkType選擇元素中刪除兩個選項。

我該怎麼做？它在文檔中說使用remove函數，但我不明白如何將它指向正確的元素。

http://docs.ckeditor.com/#!/api/CKEDITOR.ui.dialog.select

Answer 1

我們正在使用這種從對話框中刪除linkType和其他多餘的東西：

CKEDITOR.on('dialogDefinition', function(ev) { 
    var dialogName = ev.data.name; 
    var dialogDefinition = ev.data.definition; 
    if (dialogName == 'link') { 
     //REMOVE NOT REQUIRED TABS 
     dialogDefinition.removeContents('upload'); 
     dialogDefinition.removeContents('advanced'); 

     var infoTab = dialogDefinition.getContents('info'); 
     //REMOVE COMBO 
     infoTab.remove('linkType'); 
    } 
}); 

編輯： - 作爲this page和this answer描述，你可以得到元素，併爲它指定的選項。

var infoTab = dialogDefinition.getContents('info'); 
//REMOVE COMBO 
var lt=infoTab.get('linkType'); 
lt['items']=[['URL','Link to URL']]; 

Answer 2

我只是找到了答案在這裏：http://ckeditor.com/forums/Support/Remove-options-link-drop-down

CKEDITOR.on('dialogDefinition', function(ev) { 
    // Take the dialog name and its definition from the event 
    // data. 
    var dialogName = ev.data.name; 
    var dialogDefinition = ev.data.definition; 

    // Check if the definition is from the dialog we're 
    // interested on (the "Link" dialog). 
    if (dialogName == 'link') { 
     // Get a reference to the "Link Info" tab. 
     var infoTab = dialogDefinition.getContents('info'); 

     // Get a reference to the link type 
     var linkOptions = infoTab.get('linkType'); 

     // set the array to your preference 
     linkOptions['items'] = [['URL', 'url'], ['Link to anchor in the text', 'anchor']]; 
    } 
});