2013-03-08 80 views
0

我有麻煩從第三個表中獲取記錄時,當我把條件。我收到錯誤丟失列MonthlyReturns丟失。但是,如果我拿走了月度返回條件,我會得到所有3個關聯的表。cakephp hasmany與條件

的表是公司,員工和MonthlyReturns

在MonthlyReturnsController.php我發現代碼:

$conditions = array("Employee.active" => true, "Employee.start" => $start, "NOT" => array("MonthlyReturn.month" => $date)); 
$empl = $this->MonthlyReturn->Employee->find('all', array('conditions' => $conditions)); 

員工型號:

/** 
* belongsTo associations 
* 
* @var array 
*/ 
public $belongsTo = array(
    'Company' => array(
     'className' => 'Company', 
     'foreignKey' => 'company_id', 
     'conditions' => '', 
     'fields' => '', 
     'order' => '' 
    ) 
); 

/** 
* hasMany associations 
* 
* @var array 
*/ 
public $hasMany = array(
    'MonthlyReturn' => array(
     'className' => 'MonthlyReturn', 
     'foreignKey' => 'employee_id', 
     'dependent' => false, 
     'conditions' => '', 
     'fields' => '', 
     'order' => '', 
     'limit' => '', 
     'offset' => '', 
     'exclusive' => '', 
     'finderQuery' => '', 
     'counterQuery' => '' 
    ) 
); 

UPDATE:

我有試圖做一個左連接。現在我收回所有記錄,並且沒有顯示在當月的ReturnReturns中沒有記錄的員工。

我得到的SQL是

[query] => SELECT `Employee`.`id`, `Employee`.`company_id`,`Employee`.`p45_issued`, `Company`.`id`, `Company`.`member_number` 
FROM `employees` AS `Employee` 
left JOIN `monthly_returns` AS `MonthlyReturn` ON (`MonthlyReturn`.`employee_id` = `Employee`.`id`) 
LEFT JOIN `companies` AS `Company` ON (`Employee`.`company_id` = `Company`.`id`) 
WHERE NOT (`MonthlyReturn`.`month` = '2013-03-01') 

$options['joins'] = array(
    array('table' => 'monthly_returns', 
     'alias' => 'MonthlyReturn', 
     'type' => 'left', 
     'conditions' => array(
      'MonthlyReturn.employee_id = Employee.id' 
     ) 
    ), 
); 

$options['conditions'] = array("Employee.p45_issued" => false, "NOT" => array("MonthlyReturn.month" => $last_month)); 


$empl = $this->MonthlyReturn->Employee->find('all', $options); 

更新2

我設法得到通過使用SQL diectly我想要的記錄。我不喜歡這樣做,所以如果有人知道正確的cakephp方式?

$emps_overdue = $this->Employee->query("SELECT employees.*, companies.`name`, companies.`id` 

    FROM employees INNER JOIN companies ON employees.company_id = companies.id 

    LEFT JOIN monthly_returns ON monthly_returns.employee_id = employees.id 

    AND monthly_returns.month = '$last_month' 

    WHERE monthly_returns.id IS NULL AND employees.p45_issued = false"); 
+0

快速建議,當深入探討關係和應用條件時,試圖研究可遏制的行爲。 – Ankit 2013-03-08 17:27:45

+0

是的,我已經開始看它,謝謝 – 2013-03-08 17:55:44

回答

0

試着研究可容忍的行爲,它會讓你的任務更容易。