我一直在嘗試上傳一個StorageFile（主要是圖像文件）到一個PHP文件，以便它可以保存到服務器中。將StorageFile上傳到PHP文件

ViewModel.cs

public async Task<bool> uploadFile(StorageFile file) 
{ 
    try 
    { 
     using (HttpMultipartFormDataContent form = new HttpMultipartFormDataContent()) 
      { 
       using (IInputStream fileStream = await file.OpenSequentialReadAsync()) 
       { 
        HttpStreamContent streamContent = new HttpStreamContent(fileStream); 
        form.Add(streamContent, "file", file.Name); 

        using (HttpClient client = new HttpClient()) 
        { 
         using (HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, new Uri("localhost/uploadFile.php"))) 
         { 
          request.Content = form; 
          HttpResponseMessage response = await client.SendRequestAsync(request); 
          Debug.WriteLine("\nRequest: " + request.ToString()); 
          Debug.WriteLine("\n\nResponse: " + response.ToString()); 
         } 
        } 
       } 
      } 
      return true; 
    } 
    catch (Exception e) 
    { 
     Debug.WriteLine(e.Message); 
     return false; 
    } 
}

uploadFile.php

<?php 
$uploaddir = 'uploads/'; 
$uploadedFile = $uploaddir . basename($_FILES['file']['name']); 

if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadedFile)){ 
    echo 'File upload success!'; 
} else { 
    echo 'Possible file upload attack!'; 
} 
?>

問題是，當我嘗試上傳一個文件，它把我的錯誤The object has been closed. (Exception from HRESULT: 0X80000013)和Exception thrown: 'System.ObjectDisposedException' in mscorlib.ni.dll ..我不明白，我在using聲明裏面做文件上傳，怎麼處理？難道我做錯了什麼？

調試表明我這個

請求：方法：POST，RequestUri： 'http://localhost/uploadFile.php'，內容：Windows.Web.Http.HttpMultipartFormDataContent，TransportInformation：ServerCertificate： ''，ServerCertificateErrorSeverity：無，ServerCertificateErrors： {}，ServerIntermediateCertificates：{}，Headers：{Accept-Encoding：gzip，deflate} {Content-Length：27749，Content-Type：multipart/form-data;邊界= 9955f08b-e82d-428b-82e1-3197e5011ccd}

響應：狀態碼：200，ReasonPhrase：'OK'，版本：2，內容：Windows.Web.Http.HttpStreamContent，標題：{連接：Keep-Alive ，Server：Apache/2.4.18（Ubuntu），Keep-Alive：timeout = 5，max = 100，Date：Sun，2016年11月6日04:02:40 GMT} {Content-Length：28，Content-Type：text/HTML; charset = UTF-8}

來源

2016-11-05 rydev

Using statement提供了一種方便的語法，可確保正確使用IDisposable對象。簡而言之，它可以幫助您執行Dispose()方法。所以，你的代碼等於：

HttpMultipartFormDataContent form = new HttpMultipartFormDataContent();    
IInputStream fileStream = await file.OpenSequentialReadAsync(); 
HttpStreamContent streamContent = new HttpStreamContent(fileStream); 
form.Add(streamContent, "file", file.Name);  
HttpClient client = new HttpClient();    
HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, new Uri("http://127.0.0.1:9096/hello.php")); 
request.Content = form;  
HttpResponseMessage response = await client.SendRequestAsync(request); 
Debug.WriteLine("\nRequest: " + request.ToString()); 
Debug.WriteLine("\n\nResponse: " + response.ToString()); 
request.Dispose(); 
client.Dispose(); 
fileStream.Dispose(); 
form.Dispose();

您將得到在form.Dispose();代碼行除外。原因是HttpMultipartFormDataContent.Add方法不需要配置。我認爲，不需要配置的非託管資源，HttpMultipartFormDataContent類的其他方法如ReadAsBufferAsync可能需要配置。

更新您的代碼如下所示，不會拋出異常closed：

HttpMultipartFormDataContent form = new HttpMultipartFormDataContent(); 
using (IInputStream fileStream = await file.OpenSequentialReadAsync()) 
{ 
    HttpStreamContent streamContent = new HttpStreamContent(fileStream); 
    form.Add(streamContent, "file", file.Name); 

    using (HttpClient client = new HttpClient()) 
    { 
     using (HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, new Uri("http://127.0.0.1:9096/hello.php"))) 
     { 
      request.Content = form; 
      HttpResponseMessage response = await client.SendRequestAsync(request); 
      Debug.WriteLine("\nRequest: " + request.ToString()); 
      Debug.WriteLine("\n\nResponse: " + response.ToString()); 
     } 
    } 
}

來源

2016-11-07 10:11:56

將StorageFile上傳到PHP文件

ViewModel.cs

uploadFile.php

回答

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