另一雙眼睛可以檢查我的php代碼，看看爲什麼當某人向表單中提交了某些內容時，它會顯示兩次？

Question

我正在學習如何製作一個顯示提交內容的表單。當我向表單提交信息時，信息顯示兩次，我不知道爲什麼。我的代碼可能有很多錯誤，因爲我仍然是一個noob這個。我仔細檢查了一切，看看它爲什麼顯示兩次，我似乎無法找到問題。

<?php 
$mysqli = new mysqli("localhost","root", "", "hits"); 

if(!$mysqli){ 
    die('Could not connect: ' . mysqli_connect_error()); 
} 

$db_selected = mysqli_select_db($mysqli, "hits"); 

if(!$db_selected){ 
    die('can not use' . "hits" . ': ' . mysqli_connect_error()); 
} 

$hit = $_POST['hit']; 
$amount = $_POST['amount']; 
$category = $_POST['category']; 

$result = mysqli_query($mysqli, "INSERT into hit (hit, amount, category) VALUES ('$hit', '$amount', '$category')"); 

if(!mysqli_query($mysqli, "INSERT into hit (hit, amount, category) VALUES ('$hit', '$amount', '$category')")){ 
    die('Error: ' . mysql_Error()); 
} 

$data = $mysqli->query("SELECT * FROM hit"); 

while($row = $data->fetch_assoc()) { 

Print "<tr>"; 
Print "<th>Hit:</th> <td>".$row['hit'] . "</td> "; 
Print "<th>Amount:</th> <td>".$row['amount'] . " </td>"; 
Print "<th>Category:</th> <td>".$row['category'] . "</td></tr> "; 
Print "<br><br/>"; 
Print "</table>"; 
// array_sum 
} 

?> 

謝謝。

Answer 1

您運行查詢兩次。

$result = mysqli_query($mysqli, "INSERT into hit (hit, amount, category) VALUES ('$hit', '$amount', '$category')"); 

if(!mysqli_query($mysqli, "INSERT into hit (hit, amount, category) VALUES ('$hit', '$amount', '$category')")){ 
    die('Error: ' . mysql_Error()); 
} 

我想你的意思：

if(! $result){ 
    die('Error: ' . mysql_Error()); 
} 

我會改變使用PDO for databases though。

Answer 2

嘗試刪除這一行：

while($row = $data->fetch_assoc()) { 

Print "<tr>"; 
Print "<th>Hit:</th> <td>".$row['hit'] . "</td> "; 
Print "<th>Amount:</th> <td>".$row['amount'] . " </td>"; 
Print "<th>Category:</th> <td>".$row['category'] . "</td></tr> "; 
Print "<br><br/>"; 
Print "</table>"; // Remove This 
// array_sum 
} 

，並把它放在while語句