無論數組是由另一個數組的任何值

Question

我有一個數組a = ["1","2","3","6","7"]和另一個數組b = ["2","4","7"]。我想檢查a中是否存在b的任何內容。

Answer 1

使用& Ruby的運算符，它會返回一個數組，其值爲intersection兩個數組，下面是一個例子。

pry(main)> a = ["1","2","3","6","7"] 
=> ["1", "2", "3", "6", "7"] 
pry(main)> b = ["2","4","7"] 
=> ["2", "4", "7"] 
pry(main)> a & b 
=> ["2", "7"] 
pry(main)> (a & b).empty? 
=> false 

在Rails中，你也可以使用blank?

pry(main)> (a & b).blank? 
=> false 

希望上面的例子可以幫助

Answer 2

就是這麼簡單：

(a & b).blank? 

實際上這是什麼做的是，它需要兩個數組的intersection並返回結果，然後檢查結果是否爲bla NK /空。

Answer 3

你可以做

a = ["1","2","3","6","7"] 
b = ["2","4","7"] 
b.any? { |e| a.include?(e) }