1
我正在做Scala和Play的第一個應用程序!在我使用WebSocket的時候,就像他們在聊天室示例中一樣,到目前爲止,我可以向我的服務器發送消息,但我似乎無法理解我可以「處理」從客戶那裏獲得的這些消息,我也想知道如果我可以從我的服務器發送JSON數組我的客戶:服務器Scala與Play的響應
@Singleton
class HomeController @Inject()(cc: ControllerComponents)
(implicit actorSystem: ActorSystem,
mat: Materializer,
executionContext: ExecutionContext)
extends AbstractController(cc) {
private type WSMessage = String
private val logger = Logger(getClass)
private implicit val logging = Logging(actorSystem.eventStream, logger.underlyingLogger.getName)
// chat room many clients -> merge hub -> broadcasthub -> many clients
private val (chatSink, chatSource) = {
// Don't log MergeHub$ProducerFailed as error if the client disconnects.
// recoverWithRetries -1 is essentially "recoverWith"
val source = MergeHub.source[WSMessage]
.log("source")
.recoverWithRetries(-1, { case _: Exception ⇒ Source.empty })
val sink = BroadcastHub.sink[WSMessage]
source.toMat(sink)(Keep.both).run()
}
private val userFlow: Flow[WSMessage, WSMessage, _] = {
Flow.fromSinkAndSource(chatSink, chatSource)
}
def index: Action[AnyContent] = Action { implicit request: RequestHeader =>
val webSocketUrl = routes.HomeController.chat().webSocketURL()
logger.info(s"index: ")
Ok(views.html.index(webSocketUrl))
}
def chat(): WebSocket = {
WebSocket.acceptOrResult[WSMessage, WSMessage] {
case rh if sameOriginCheck(rh) =>
Future.successful(userFlow).map { flow =>
Right(flow)
}.recover {
case e: Exception =>
val msg = "Cannot create websocket"
logger.error(msg, e)
val result = InternalServerError(msg)
Left(result)
}
case rejected =>
logger.error(s"Request ${rejected} failed same origin check")
Future.successful {
Left(Forbidden("forbidden"))
}
}
}
}
順便說一句,我通過jQuery函數發送從我的客戶端的消息。
編輯我要處理這個消息的方法是將它們作爲參數傳遞給函數,該函數將返回字符串或整數數組,我要返回給客戶端