我是新來的rails,我創建了一個博客,看起來像一個Esquire網站,他們有最新的六個職位在頂部該頁面排列在一起,然後稍微向下一頁,他們將有一個大的帖子本身繼續發佈數組,所以它將確實是第7篇文章,然後稍微向下,你會有下三個職位8-11等。Rails:選擇博客的前6個帖子,然後選擇第7個等等
我正在嘗試使控制器成爲一個陣列,在那裏我可以先調用前六個項目,然後再分別在主頁後面調用第七個項目。
帖子控制器:
class PostsController < ApplicationController
before_action :set_post, only: [:show, :edit, :update, :destroy]
before_action :authenticate_user!, except: [:index, :show]
# GET /posts
# GET /posts.json
def index
@posts = Post.all
end
# GET /posts/1
# GET /posts/1.json
def show
@posts = Post.all.order('created_at DESC')
@topsix = @posts.take(6)
end
# GET /posts/new
def new
@post = current_user.posts.build
@categories = Category.all.map{|c| [ c.name, c.id ] }
end
# GET /posts/1/edit
def edit
@categories = Category.all.map{|c| [ c.name, c.id ] }
end
# POST /posts
# POST /posts.json
def create
@post = current_user.posts.build(post_params)
@post.category_id = params[:category_id]
respond_to do |format|
if @post.save
format.html { redirect_to @post, notice: "post was successfully created." }
format.json { render :show, status: :created, location: @post }
else
format.html { render :new }
format.json { render json: @post.errors, status: :unprocessable_entity }
end
end
end
# PATCH/PUT /posts/1
# PATCH/PUT /posts/1.json
def update
respond_to do |format|
if @post.update(post_params)
format.html { redirect_to @post, notice: 'Post was successfully updated.' }
format.json { render :show, status: :ok, location: @post }
else
format.html { render :edit }
format.json { render json: @post.errors, status: :unprocessable_entity }
end
end
@post.category_id = params[:category_id]
end
# DELETE /posts/1
# DELETE /posts/1.json
def destroy
@post.destroy
respond_to do |format|
format.html { redirect_to posts_url, notice: 'Post was successfully destroyed.' }
format.json { head :no_content }
end
end
private
# Use callbacks to share common setup or constraints between actions.
def set_post
@post = Post.find(params[:id])
end
# Never trust parameters from the scary internet, only allow the white list through.
def post_params
params.require(:post).permit(:title, :excerpt, :create_date, :author, :body, :category_id, :image)
end
end
首頁控制器:
class HomeController < ApplicationController
def index
@posts = Post.all.order('created_at DESC')
@topsix = @posts.take(6)
@first3 = @posts.order('created_at DESC').take(3)
@sidebar = @posts.take(3)
@first4 = @posts.take(4)
@first = @posts.take(1)
end
end
在哪裏,我呼籲它在主頁上:
<div class="row no-gutters">
<% @topsix.select { |post| post > 6 } %>
<div class="col-md-2"><%= image_tag post.image.url(:large), class: "img-responsive"%>
<h6 class="small-title"><%= link_to post.title, post %></h6>
</div>
<% end %>
</div>
你需要的是:1)第一個6個職位,2)第7個職位,和3)其餘? –
是的,正好和主頁上顯示 – Ian
@Ian,請測試我的答案。 – fabriciofreitag