Spring JsonExceptionMapper ExceptionMapper處理。

當我啓動我的服務器時，我在我的weblogic控制檯中出現以下錯誤。Spring JsonExceptionMapper ExceptionMapper處理。

重度：在參數索引缺少依賴於構造公共com.test.mine.exception.JsonExceptionMapper（java.lang.String中，com.fasterxml.jackson.core.JsonLocation）0 嚴重：缺少依賴於在參數指標1

構造公共com.test.mine.exception.JsonExceptionMapper（java.lang.String中，com.fasterxml.jackson.core.JsonLocation）下面是我的Java代碼。

package com.test.mine.exception; 

import javax.ws.rs.core.MediaType; 
import javax.ws.rs.core.Response; 
import javax.ws.rs.core.Response.Status; 
import javax.ws.rs.ext.ExceptionMapper; 
import javax.ws.rs.ext.Provider; 

import org.slf4j.Logger; 
import org.slf4j.LoggerFactory; 
import org.springframework.stereotype.Service; 

import com.fasterxml.jackson.core.JsonLocation; 
import com.fasterxml.jackson.core.JsonParseException; 

@Provider 
@Service 
public class JsonExceptionMapper extends JsonParseException implements ExceptionMapper { 

    public JsonExceptionMapper(String msg, JsonLocation loc) { 
     super(msg, loc); 
     // TODO Auto-generated constructor stub 
    } 

    private static final Logger LOGGER = LoggerFactory.getLogger(JsonExceptionMapper.class); 

    protected Logger getLogger() { 
     return LOGGER; 
    } 

    public Status getStatus(JsonParseException thr) { 
     return Status.BAD_REQUEST; 
    } 

    @Override 
    public Response toResponse(Throwable arg0) { 
     // TODO Auto-generated method stub 
     return Response.status(Status.BAD_REQUEST).type(MediaType.APPLICATION_JSON_TYPE).build(); 
    } 
}

來源

2016-03-04 user2045810