2016-05-13 63 views
0

我在我的應用程序上嘗試了一些新功能,因爲之前的操作方式並非真正最佳,可以在貨幣表中無限次地重複貨幣,這不是我真正想要的希望未來(考慮可擴展性和未來增長)。Relationship,crud silex and propel orm

所以我繼續努力,閱讀文檔上,並在ORM Cheatsheet得到了許多一對多(我想不完全是,但它的確定,因爲它的工作再次擴展性和未來發展的思考)

<xml> 
<table name="countries"> 
    <column name="id" type="INTEGER" required="true" primaryKey="true" autoIncrement="true" /> 
    <column name="name" type="VARCHAR" size="128" required="true" /> 
    <column name="country_code" phpName="CountryCode" type="VARCHAR" size="7" required="true" /> 
    <column name="status" phpName="Status" type="BOOLEAN" required="true" defaultValue="false" /> 

    <unique name="IX_UQ_banks_id"> 
     <unique-column name="id"/> 
    </unique> 

    <unique name="IX_UQ_currencies_id"> 
     <unique-column name="id"/> 
    </unique> 

    <behavior name="timestampable" /> 
    <behavior name="soft_delete" /> 
    <behavior name="versionable" /> 
</table> 

<table name="currencies"> 
    <column name="id" type="INTEGER" required="true" primaryKey="true" autoIncrement="true" /> 
    <column name="name" phpName="Name" type="VARCHAR" size="128" required="true" /> 
    <column name="code" phpName="Code" type="VARCHAR" size="7" required="true" /> 
    <column name="symbol" phpName="Symbol" type="VARCHAR" size="12" required="true" /> 

    <unique name="IX_UQ_countries_id"> 
     <unique-column name="id"/> 
    </unique> 

    <behavior name="timestampable" /> 
    <behavior name="soft_delete" /> 
</table> 

<table name="country_has_currency" isCrossRef="true"> 
    <column name="countries_id" type="INTEGER" required="true" primaryKey="true" /> 
    <column name="currencies_id" type="INTEGER" required="true" primaryKey="true" /> 

    <foreign-key 
     foreignTable="countries" 
     defaultJoin="Criteria::LEFT_JOIN" 
     onDelete="setnull" 
     onUpdate="cascade" 
     phpName="Countries"> 
     <reference local="countries_id" foreign="id" /> 
    </foreign-key> 

    <foreign-key 
     foreignTable="currencies" 
     defaultJoin="Criteria::INNER_JOIN" 
     onDelete="setnull" 
     onUpdate="cascade"> 
     <reference local="currencies_id" foreign="id" /> 
    </foreign-key> 
</table> 

```

我似乎無法找到的是插入新記錄後保存此對象的正確方法。 由於我正在寫的代碼我可以得到貨幣一個國家有使用symfony2國際組件(im使用silex tho),所以問題出現在這裏:

添加新的國家,獲取貨幣,檢查是否貨幣如果存在,則與現有貨幣和新國家建立關係,如果不存在,則插入新的國家和新貨幣。

回答

0

明白了。

<!-- language: php --> 
$country = new Countries(); 
$country->setName($data['country_name']); 
$country->setCountryCode($data['country_code']); 
$country->setStatus($data['country_status']); 

$currency = new Currencies(); 
$currency->setName($data['currency_name']); 
$currency->setCode($data['currency_code']); 
$currency->setSymbol($data['currency_symbol']); 

$country->addCurrencies($currency); 

$country->save();