問候善良的人,PHP/MySQL的:保存值數據庫
我在使用PHP/MySQL和我是通過一個基本的任務,我碰釘子工作的編碼一個新人,當它來保存的值文本字段和複選框指向mysql數據庫。
這是我所能做的,但我仍然無法在數據庫中保存記錄。
我做錯了什麼或者我失去了什麼?
上午使用Macromedia的Dreamweaver 8,阿帕奇/ 2.2.12(Win32的)DAV/2的mod_ssl/2.2.12的OpenSSL/0.9.8k mod_autoindex_color PHP/5.3.0的mod_perl/2.0.4的Perl/v5.10.0 MySQL的客戶端版本5.1.37 PHP擴展:mysqli的
$con = mysqli_connect("localhost", "root", "");
if (!$con) {
exit('Connect Error (' . mysqli_connect_errno() . ') '
. mysqli_connect_error());
}
if ($_POST['textfield'] == "") {
$FieldsEmpty= true;
}
else {
if ($FieldsEmpty) echo "Please enter all the fields<br/>";
}
if($_POST['Submit2'] == "Submit")
{
$VarName = $_POST['textfield'];
$VarOrg = $_POST['textfield2'];
$VarAddress = $_POST['textfield3'];
$VarPhone=$_POST ['textfield4'];
$VarEmail=$_POST['textfield5'];
$VarAccomodation=$_POST['checkbox'];
$VarEntertainment=$_POST['checkbox2'];
$VarTourOP=$_POST['checkbox3'];
$VarDomesticTourism=$_POST['checkbox4'];
$VarTourism=$_POST['checkbox5'];
$VarTravelmgt=$_POST['checkbox6'];
$VarSupport=$_POST['checkbox7'];
$VarMedia=$_POST['checkbox8'];
$VarDoc1=$_POST[$_FILES["file"]["name"]];
$VarDoc2=$_POST[$_FILES["file2"]["name"]];
$VarDoc3=$_POST[$_FILES["file3"]["name"]];
$Vardoc4=$_POST[$_FILES["file4"]["name"]];
$sql = "Insert into nominatons_tbl(name,org,address,phone,email,best_accomodation,best_entertainment,best_touroperator,best_domestictourism,best_tourism,best_travelmgt,best_support,best_media,doc1,doc2,doc3,doc4) VALUES (".PrepSQL($VarName) . ", " .PrepSQL($VarOrg) . ", " .PrepSQL($VarAddress) . ", " .PrepSQL($VarPhone) . ", " .PrepSQL($VarEmail) . ", " .PrepSQL($VarAccomodation) . ", " .PrepSQL($VarEntertainment) . ", " .PrepSQL($VarTourOP) . ", " .PrepSQL($VarDomesticTourism) . ", " .PrepSQL($VarTourism) . ", " .PrepSQL($VarTravelmgt) . ", " .PrepSQL($VarSupport) . ", " .PrepSQL($VarMedia) . ", " .PrepSQL($VarDoc1) . ", " .PrepSQL($VarDoc2) . ", " .PrepSQL($VarDoc3) . ", " .PrepSQL($Vardoc4) . ")";
mysql_query($sql);
echo "Nomination submited <br />";
}
function PrepSQL($value)
{
// Stripslashes
if(get_magic_quotes_gpc())
{
$value = stripslashes($value);
}
// Quote
$value = "'" . mysql_real_escape_string($value) . "'";
return($value);
}
什麼是錯誤信息? – rkosegi 2012-03-08 15:36:36
請運行您正在使用的phpmyadmin或數據庫的查詢,並顯示您在插入數據時所得到的錯誤。 – Milap 2012-03-08 15:36:53