問題有關admin.py list_display

Question

#admin.py 
class GameListAdmin(admin.ModelAdmin): 
    list_display = ['game', 'position'] 
    ordering = ('position',) 

class GameAdmin(admin.ModelAdmin): 
    list_display = ['name', 'status'] 
    actions = [make_published] 

#models.py 
class Game(models.Model): 
    name = models.CharField(max_length=200) 
    status = models.CharField(max_length=1, choices=STATUS_CHOICES) 

    def __unicode__(self): 
     return self.name 

class GameList(models.Model): 
    game = models.ForeignKey(Game) 
    position = models.IntegerField() 

    def __unicode__(self): 
     return self.game.name 

我試圖表現出game.status在GameListAdmin的list_display但不 知道如何做一個使用ForeignKey的在Admin.py

任何想法向後查找？

Answer 1

你可以這樣說：

def get_status(obj): 
    return '%s' % (obj.game.status) 
get_status.short_description = 'Status' 

class GameListAdmin(admin.ModelAdmin): 
    list_display = ['game', 'position', get_status] 

見docs。

Answer 2

你總是可以定義自己列，如DOC解釋說：http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display

例如：

class GameListAdmin(admin.ModelAdmin): 
    list_display = ['game_status', 'position'] 
    ordering = ('position',) 

    def game_status(self, obj): 
     return obj.game.status 
    game_status.short_description = 'Game status'