編譯錯誤：鏈接器命令失敗，退出代碼1

Question

我是C++的新手，試圖製作一個簡單的程序。

但我得到這個錯誤：

Undefined symbols for architecture x86_64: 
    "_main", referenced from: 
    implicit entry/start for main executable 
ld: symbol(s) not found for architecture x86_64 
clang: error: linker command failed with exit code 1 (use -v to see invocation) 
[Finished in 0.4s with exit code 1] 

從這個代碼：

#include <iostream> 
using namespace std; 

// Lets add some global variables 
int FirstNumber = 0; 
int SecondNumber = 0; 
int MultiNum = 0; 

void MultiNumbers() 
{ 
    cout << "Enter the first number: "; 
    cin >> FirstNumber; 

    cout << "Enter the second number: "; 
    cin >> SecondNumber; 

    // Multiply two numbers... 
    MultiNum = FirstNumber * SecondNumber; 

    // Display result 
    cout << "Displaying result from MultiNumbers(): "; 
    cout << FirstNumber << " x " << SecondNumber; 
    cout << " = " << MultiNum << endl; 
} 
int Main() 
{ 
    cout << "This program will help you to multiply two numbers" << endl; 

    // Now call the function that does all the work 
    MultiNumbers(); 

    cout << "Displaying from main(): "; 

    // This line will not compile and work because of the global variables 
    cout << FirstNumber << " x " << SecondNumber; 
    cout << " = " << MultiNum << endl; 

    return 0; 
} 

我已經試過檢查我的崇高的編譯器，在終端使用g ++ -o測試TEST.CPP

編譯

但似乎沒有任何幫助。

我的理解是，我定義MultiNumbers（）上面，然後我打電話給它在main（）...但我似乎已經錯過了一些東西......

建議？

Answer 1

C++區分大小寫。這：

int Main() 

應該

int main()