Scrapy通過IP地址抓取本地網站

Question

我仍在嘗試Scrapy，並試圖抓取本地網絡上的網站。該網站的IP地址爲192.168.0.185。這是我的蜘蛛：

from scrapy.spider import BaseSpider 
class 192.168.0.185_Spider(BaseSpider): 
     name = "192.168.0.185" 
     allowed_domains = ["192.168.0.185"] 
     start_urls = ["http://192.168.0.185/"] 

     def parse(self, response): 
      print "Test:", response.headers 

然後在我的蜘蛛我會執行這個shell命令來運行蜘蛛的同一目錄：

scrapy crawl 192.168.0.185 

而且我得到一個非常醜陋，無法讀取錯誤信息：

2012-02-10 20:55:18-0600 [scrapy] INFO: Scrapy 0.14.0 started (bot: tutorial) 
2012-02-10 20:55:18-0600 [scrapy] DEBUG: Enabled extensions: LogStats, 
TelnetConsole,  CloseSpider, WebService, CoreStats, MemoryUsage, SpiderState 
2012-02-10 20:55:18-0600 [scrapy] DEBUG: Enabled downloader middlewares:  
HttpAuthMiddleware, DownloadTimeoutMiddleware, UserAgentMiddleware, RetryMiddleware, 
DefaultHeadersMiddleware, RedirectMiddleware, CookiesMiddleware, 
HttpCompressionMiddleware, ChunkedTransferMiddleware, DownloaderStats 
2012-02-10 20:55:18-0600 [scrapy] DEBUG: Enabled spider middlewares: 
HttpErrorMiddleware, OffsiteMiddleware, RefererMiddleware, UrlLengthMiddleware, 
DepthMiddleware 2012-02-10 20:55:18-0600 [scrapy] DEBUG: Enabled item pipelines: 
Traceback (most recent call last): File "/usr/bin/scrapy", line 5, in <module> 
pkg_resources.run_script('Scrapy==0.14.0', 'scrapy') 
File "/usr/lib/python2.6/site-packages/pkg_resources.py", line 467, in run_script 
self.require(requires)[0].run_script(script_name, ns) 
File "/usr/lib/python2.6/site-packages/pkg_resources.py", line 1200, in run_script 
execfile(script_filename, namespace, namespace) 
File "/usr/lib/python2.6/site-packages/Scrapy-0.14.0-py2.6.egg/EGG-INFO/scripts 
/scrapy", line 4, in <module> 
execute() 
File "/usr/lib/python2.6/site-packages/Scrapy-0.14.0-py2.6.egg/scrapy/cmdline.py", 
line 132, in execute 
_run_print_help(parser, _run_command, cmd, args, opts) 
File "/usr/lib/python2.6/site-packages/Scrapy-0.14.0-py2.6.egg/scrapy/cmdline.py", 
line 97, in _run_print_help func(*a, **kw) 
File "/usr/lib/python2.6/site-packages/Scrapy-0.14.0-py2.6.egg/scrapy/cmdline.py", 
line 139, in _run_command cmd.run(args, opts) 
File "/usr/lib/python2.6/site-packages/Scrapy-0.14.0-py2.6.egg/scrapy/commands 
/crawl.py", line 43, in run 
spider = self.crawler.spiders.create(spname, **opts.spargs) 
File "/usr/lib/python2.6/site-packages/Scrapy-0.14.0-py2.6.egg/scrapy 
/spidermanager.py", line 43, in create 
raise KeyError("Spider not found: %s" % spider_name) 
KeyError: 'Spider not found: 192.168.0.185' 

所以後來我又蜘蛛，這實際上是一樣的第一個，但它採用的是域名而不是IP地址。這個工作得很好。有誰知道交易是什麼？我如何才能讓Scrapy通過IP地址而不是域名來抓取網站？

from scrapy.spider import BaseSpider 
class facebook_Spider(BaseSpider): 
    name = "facebook" 
    allowed_domains = ["facebook.com"] 
    start_urls = ["http://www.facebook.com/"] 


    def parse(self, response): 
     print "Test:", response.headers 

Answer 1

class 192.168.0.185_Spider(BaseSpider): 
    ... 

不能使用與數字開頭或包含在Python點的類名。見文檔Identifiers and keywords

您可以創建這種蜘蛛有正確的名稱：

$ scrapy startproject testproj 
$ cd testproj 
$ scrapy genspider testspider 192.168.0.185 
    Created spider 'testspider' using template 'crawl' in module: 
    testproj.spiders.testspider 

蜘蛛定義看起來就像這樣：

class TestspiderSpider(CrawlSpider): 
    name = 'testspider' 
    allowed_domains = ['192.168.0.185'] 
    start_urls = ['http://www.192.168.0.185/'] 
    ... 

，也許你應該從start_urls刪除www。要開始爬行，使用蜘蛛名代替主機：

$ scrapy crawl testspider 

$ scrapy crawl testspider