哪些錯誤在我的代碼,當我測試它的輸出變爲寫,但在我的瀏覽器顯示,說的「警告警告:odbc_fetch_row():37是不是在線729上的C:\ xampp \ htdocs \ webinterface \ requests.php中有效的ODBC結果資源「警告:odbc_fetch_row():37是不是一個有效的ODBC結果資源
我不知道這是什麼意思,sql語句結果在dbexplorer中很好。順便說一句,可能數據庫是悖論,並使用odbc連接我的PHP悖論。
有人能幫助我嗎?非常感謝你
我下面的代碼:
$connectionstring = odbc_connect(DB_DNS,DB_USER,DB_PASS);
$auditRequestNo = "";
$ar_requestno = "";
$svemp1 = "";
$svemp2 = "";
foreach($uArr as $arNo){
$ar_requestno .= (!empty($ar_requestno))? ",".$arNo : $arNo;
$auditRequestNo .= (!empty($auditRequestNo))? ",".sprintf("%08d", $arNo) : sprintf("%08d", $arNo);
}
$query = "SELECT SV_EmployeeNo,Sv_EmployeeNo2 \r\n".
"FROM AuthorizationRequests \r\n".
"WHERE ARNO IN (".$ar_requestno.") ";
$result = odbc_do($connectionstring, $query);
while(odbc_fetch_row($result)){
$svemp1 = odbc_result($result,1);
$svemp2 = odbc_result($result,2);
switch(intval($s)){
case 1: // approved
if(empty($svemp1) and empty($svemp2)){
$update_fields = "flag=0, DateApproved = { d '".date('Y-m-d')."' } , SV_EmployeeNo=".$_SESSION['uen']." ";
$update_query = "UPDATE AuthorizationRequests \r\n".
"SET ".$update_fields."\r\n ".
"WHERE ArNo IN(".$ar_requestno.")";
$update_query = odbc_exec($connectionstring, $update_query);
odbc_close($connectionstring);
}else if(!empty($svemp1) and empty($svemp2) and $svemp1 != $_SESSION['uen']){
$update_fields = "flag=".$s.", DateApproved2 = { d '".date('Y-m-d')."' } , SV_EmployeeNo2=".$_SESSION['uen']." ";
$update_query = "UPDATE AuthorizationRequests \r\n".
"SET ".$update_fields."\r\n ".
"WHERE ArNo IN(".$ar_requestno.")";
$update_query = odbc_exec($connectionstring, $update_query);
odbc_close($connectionstring);
}
#}
break;
case 2: // rejected
$update_fields = "flag=".$s.", DateApproved = { d '".date('Y-m-d')."' }, SV_EmployeeNo=".$_SESSION['uen']." ";
$update_query = "UPDATE AuthorizationRequests \r\n".
"SET ".$update_fields."\r\n ".
"WHERE ArNo IN(".$ar_requestno.")";
$update_query = odbc_exec($connectionstring, $update_query);
odbc_close($connectionstring);
break;
default: // reset
$update_fields = "flag=0, DateApproved=NULL, SV_EmployeeNo=NULL, DateApproved2=NULL, SV_EmployeeNo2=NULL";
$update_query = "UPDATE AuthorizationRequests \r\n".
"SET ".$update_fields."\r\n ".
"WHERE ArNo IN(".$ar_requestno.")";
$update_query = odbc_exec($connectionstring, $update_query);
odbc_close($connectionstring);
break;
}
}
只是一個猜測在這裏,但我會失去了'\ r \ N'在查詢字符串中的字符 – Phil 2010-12-17 03:58:46
SQL工作正常,我已經檢查txt文件中的輸出並在數據庫瀏覽器中進行測試。 – aintgel 2010-12-17 05:55:52