爲什麼我的程序掛起

Question

from random import * 

IQ = [] 
row1 = ["#", "#", "#"] 
row2 = ["#", "#", "#"] 
row3 = ["#", "#", "#"] 
board = [row1, row2, row3] 


def Display_Board(): 
    print(row1[0],"|", row1[1], "|", row1[2]) 
    print("----------") 
    print(row2[0],"|", row2[1], "|", row2[2]) 
    print("----------") 
    print(row3[0],"|", row3[1], "|", row3[2]) 

def Automated_Move(board): 
    while True: 
     RandomMove = randint(0,2) 
     if board[RandomMove][RandomMove] == "#": 
      board[RandomMove][RandomMove] = "O" 
      break 
     elif board[RandomMove][RandomMove] != "#": 
      pass 

while True: 
    #print(IQ) 
    Display_Board() 
    Row = int(input("Row: ")) - 1 
    Col = int(input("Col: ")) - 1 
    if board[Row][Col] != "X" and board[Row][Col] != "O": 
     board[Row][Col] = "X" 
     IQ.append(Row) 
     IQ.append(Col) 
    elif board[Row][Col] == "X" or board[Row][Col] == "O": 
     print("This is already Taken") 
     pass 

    Automated_Move(board) 
    print("\n") 

我想做一個簡單的基於遺傳算法的井字遊戲，我不知道它爲什麼會崩潰。 我發現它在Automated_Move函數的循環中（如果有幫助的話）

Answer 1

您的主循環永遠不會結束。有中沒有break：

while True: 
    #print(IQ) 
    Display_Board() 
    Row = int(input("Row: ")) - 1 
    Col = int(input("Col: ")) - 1 
    if board[Row][Col] != "X" and board[Row][Col] != "O": 
     board[Row][Col] = "X" 
     IQ.append(Row) 
     IQ.append(Col) 
    elif board[Row][Col] == "X" or board[Row][Col] == "O": 
     print("This is already Taken") 
     pass 

    Automated_Move(board) 
    print("\n") 

而且你Automated_Move()的while循環也遲早會進入一個永遠的循環。

def Automated_Move(board): 
    while True: 
     RandomMove = randint(0,2) 
     if board[RandomMove][RandomMove] == "#": 
      board[RandomMove][RandomMove] = "O" 
      break 
     elif board[RandomMove][RandomMove] != "#": 
      pass 

該環路僅中斷中是否存在一個board元件'#'（即元件改變至O後）。經過多次迭代後，board的所有（對角線）元素將爲'O'，因此循環將永不退出。

一個可能的解決方案是修改主迴路爲：

if any(['#' in r for r in board]): 
    Automated_Move(board) 
else: 
    break