在JSON文件中迭代多個對象

我在解析通過訪問API檢索的JSON文件。現在，我可以創建我的Offer類的一個ArrayList對象，但我只是閱讀第一個JSON對象並獲取我感興趣的字符串。我該如何去創建儘可能多的我的Offer對象在JSON文件中有嗎？在JSON文件中迭代多個對象

換句話說，我需要遍歷JSON文件並獲取所有優惠。

的JSON看起來是這樣的：

{"offer":"expiration":"2011-04-08T02:30:00Z","valid_from":"2011-04-07T12:00:31Z","business":{"address":{"state":"NY","zip":"10013","cross_streets":"Chatham Sq & Worth St","address_1":"12 Mott St","address_2":null,"city":"New York"},"phone":"2126192989","published":"2011-04-07T12:00:33Z","rescinded_at":null,"valid_to":"2011-04-08T02:00:00Z"}}, {"offer":"expiration":"2011-04-08T02:30:00Z","valid_from":"2011-04-07T12:00:31Z","business":{"address":{"state":"NY","zip":"10013","cross_streets":"Chatham Sq & Worth St","address_1":"12 Mott St","address_2":null,"city":"New York"},"phone":"2126192989","published":"2011-04-07T12:00:33Z","rescinded_at":null,"valid_to":"2011-04-08T02:00:00Z"}}, {"offer":"expiration":"2011-04-08T02:30:00Z","valid_from":"2011-04-07T12:00:31Z","business":{"address":{"state":"NY","zip":"10013","cross_streets":"Chatham Sq & Worth St","address_1":"12 Mott St","address_2":null,"city":"New York"},"phone":"2126192989","published":"2011-04-07T12:00:33Z","rescinded_at":null,"valid_to":"2011-04-08T02:00:00Z"}}

正如你可以看到，有一個又一個的報價對象...

這裏是我到目前爲止的代碼：

 ArrayList<Offer> offerList = new ArrayList<Offer>(); 

     for(String url: urls) { 
      OAuthConsumer consumer = new DefaultOAuthConsumer(CONSUMER_KEY, CONSUMER_SECRET); 
      consumer.setTokenWithSecret("", ""); 

      try { 

       URL url1 = new URL(url); 
       HttpURLConnection request = (HttpURLConnection) url1.openConnection(); 

       // sign the request 
       consumer.sign(request); 

       // send the request 
       request.connect(); 


       String JSONString = convertStreamToString(request.getInputStream()); 

       JSONObject jObject = new JSONObject(JSONString); 

       JSONObject offerObject = jObject.getJSONObject("offer"); 

       String titleValue = offerObject.getString("title"); 
       //System.out.println(titleValue); 

       String descriptionValue = offerObject.getString("description"); 
       //System.out.println(attributeValue); 
       JSONObject businessObject = offerObject.getJSONObject("business"); 
       String nameValue = businessObject.getString("name"); 

       Offer myOffer = new Offer(titleValue, descriptionValue, nameValue); 

       offerList.add(myOffer); 
       Log.v("ArrayList:", offerList.toString()); 

      } catch (Exception e) { 
       e.printStackTrace(); 

      } 
     } 
     return offerList;

來源

2011-05-13 LuxuryMode

您提交的JSON不是有效的JSON。

如果你在開頭加一個'['，結尾加一個']'，它就成爲一個有效的JSONArray。

JSONArray JavaDoc

你應該能夠做這樣的事情：

JSONArray array = new JSONArray(inputJSON); 
for(int index = 0; index < array.length(); ++index) { 
    JSONObject offerObject = array.getJSONObject(index); 
    //... your offer calculation...add offer to list... 
}

如果您的報價JSON的一個JSONObjects（你會如果你加括號像我的建議）的JSONArray ，那麼您可以遍歷JSONArray的長度，在每次傳遞時獲取您的JSONObject，並創建Offer，就像您在提供的示例中一樣。

來源

2011-05-13 05:01:07

廢話，你說得對。我用substring在文件的開始和結尾處切斷了「[」和「]」，因爲我認爲我的convertStreamToString方法正在添加它，但事實並非如此。所以我有JSONArray。你能告訴我如何遍歷數組？我遇到了麻煩...... – LuxuryMode 2011-05-13 05:04:47

我編輯了我的帖子。 – 2011-05-13 05:09:29

在JSON文件中迭代多個對象

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