1
我正在創建在線詞典Android應用程序。 我正在使用JSON來請求用戶輸入的單詞的定義。 每次單擊搜索按鈕時,此輸入都會進入變量「文本」。 然後,輸入的字被添加到API請求URL中,該URL請求URL返回定義......存儲在變量「result」中的底部方法OnPost Execute() 然後我的TextView應該被設置爲這個String。如何嵌入互聯網請求代碼並獲得在一個OnClickListener中實現的結果
因此,將整個JSON和HTTPrequest代碼放在onClickLIstener中,因爲用戶輸入總是隨時更改和請求,但即使在「public JSONObject lastTweet(String word)」錯誤之後出現「拋出ClientProtocolException」錯誤是「令牌上的語法錯誤,刪除這些令牌」我使用Enclipse Indigo。
這裏是我的代碼:
public class Dictionary extends Activity {
String finalresult;
HttpClient client = new DefaultHttpClient();
TextView ansa;
JSONObject json;
Button Search;
EditText input;
String text;
final static String URL = "http://api.wordnik.com/v4/word.json/";
final static String URL2 = "/definitions?api_key=<MY API KEY>";
String fresult;
Dictionary dic = new Dictionary();
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.dictionary);
ansa = (TextView) findViewById(R.id.ansa);
input = (EditText) findViewById(R.id.input);
Search = (Button) findViewById(R.id.search);
Search.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// TODO Auto-generated method stub
text = input.getText().toString();
public JSONObject lastTweet(String word)
throws ClientProtocolException, IOException, JSONException{
new Read().execute("text");
StringBuffer strBuff = new StringBuffer();
strBuff.append(URL);
strBuff.append(word);
strBuff.append(URL2);
HttpGet get = new HttpGet(strBuff.toString());
HttpResponse r = client.execute(get);
int status = r.getStatusLine().getStatusCode();
if (status == 200){
HttpEntity e = r.getEntity();
String data = EntityUtils.toString(e);
JSONArray timeline = new JSONArray(data);
JSONObject last = timeline.getJSONObject(0);
return last;
}else{
Toast.makeText(Dictionary.this, "error", Toast.LENGTH_LONG);
return null;
}
}
class Read extends AsyncTask<String, Integer, String>{
@Override
public String doInBackground(String... params) {
// TODO Auto-generated method stub
try {
json = lastTweet(text);
return json.getString(params[0]);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
fresult = result;
// TODO Auto-generated method stub
}
}
ansa.setText(fresult);
}
});
}
public JSONObject lastTweet(String word)
throws ClientProtocolException, IOException, JSONException{
new Read().execute("text");
StringBuffer strBuff = new StringBuffer();
strBuff.append(URL);
strBuff.append(word);
strBuff.append(URL2);
HttpGet get = new HttpGet(strBuff.toString());
HttpResponse r = client.execute(get);
int status = r.getStatusLine().getStatusCode();
if (status == 200){
HttpEntity e = r.getEntity();
String data = EntityUtils.toString(e);
JSONArray timeline = new JSONArray(data);
JSONObject last = timeline.getJSONObject(0);
return last;
}else{
Toast.makeText(Dictionary.this, "error", Toast.LENGTH_LONG);
return null;
}
}
class Read extends AsyncTask<String, Integer, String>{
@Override
public String doInBackground(String... params) {
// TODO Auto-generated method stub
try {
json = lastTweet(text);
return json.getString(params[0]);
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String result) {
fresult = result;
// TODO Auto-generated method stub
}
}
}
有什麼建議?
我做了,但我不斷收到StackOverflow錯誤,應用程序無法正常工作。 – user1559736 2012-07-28 14:53:11