從內向外繪製一個正方形的像素 - Java

Question

我想繪製一個像素的正方形，等待數組中有多少項。正方形表示數組量，所以小方塊表示小數組，大方塊表示大數組。我很難概念化我如何去做這件事？

編輯：我正在使用Java 2D。

螺旋從1開始，然後逆時針向正方形外側（即2,3,4,5等）前進。每個正方形可以用正方形表示的數據量表示。

Answer 1

public class Test { 

    enum Direction { 
     Right, 
     Up, 
     Left, 
     Down 
    } 

    public static void main(String... args) throws IOException { 

     BufferedImage image = new BufferedImage(100, 100, BufferedImage.TYPE_INT_ARGB); 

     int rgb = Color.BLACK.getRGB(); 

     Point p = new Point(50, 50); 
     Direction d = Direction.Right; 
     int currentSegmentLength = 1; 


     for (int i = 0; i < 100; i += 2) { 

      paintSegment(image, rgb, p, d, currentSegmentLength); 
      d = nextSegmentDirection(d); 

      paintSegment(image, rgb, p, d, currentSegmentLength); 
      d = nextSegmentDirection(d); 

      currentSegmentLength++; 
     } 


     ImageIO.write(image, "png", new File("test.png")); 
    } 

    private static void paintSegment(BufferedImage image, int rgb, Point p, 
      Direction d, int currentSegmentLength) { 

     for (int s = 0; s < currentSegmentLength; s++) { 
      image.setRGB(p.x, p.y, rgb); 

      switch (d) { 
      case Right: p.x++; break; 
      case Up: p.y--; break; 
      case Left: p.x--; break; 
      case Down: p.y++; break; 
      } 
     } 
    } 

    private static Direction nextSegmentDirection(Direction d) { 
     switch (d) { 
     case Right: return Direction.Up; 
     case Up: return Direction.Left; 
     case Left: return Direction.Down; 
     case Down: return Direction.Right; 

     default: throw new RuntimeException("never here"); 
     } 
    } 
}