與AWK查找和替換

我有一個名爲sso_med.txt與AWK查找和替換

 insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502683504',16,current_date, '502264160', current_date, '502264160'); 
     insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031',15,current_date, '502264160', current_date, '502264160'); 
     insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031',16,current_date, '502264160', current_date, '502264160'); 
     insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('212462117', 15, current_date, '502264160', current_date, '502264160'); 
     insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('212462117', 16, current_date, '502264160', current_date, '502264160');

我想'502689031',16,current_date,

之間引入一個空間的文件所以，我想下面的命令

awk '{gsub(/,[0-9a-zA-Z]/, ", "); print}' sso_med.txt

但我我沒有得到我期待的東西

insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502683504', 6, urrent_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 5, urrent_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 6, urrent_date, '502264160', current_date, '502264160');

來源

2017-05-25 sromit

其從CURRENT_DATE切出「c」和從數字「1」，並與空間 – sromit

AWK溶液：

awk '{ gsub(/, */, ", ", $0) }1' sso_med.txt

輸出：

insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502683504', 16, current_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 15, current_date, '502264160', current_date, '502264160'); 
insert into brs.user_components (user_name, component_id, created_date, created_by, last_updated_date, last_updated_by) values ('502689031', 16, current_date, '502264160', current_date, '502264160');

gsub(/, */, ", ", $0) - 替換/ 重新排列每個分離器（即,）與單一尾部空格

來源

2017-05-25 21:14:57 RomanPerekhrest

只要給後面參考：

awk '{gsub(/,[0-9a-zA-Z]/, " &"); print}' sso_med.txt

來源

2017-05-25 21:24:26

替換它們它引入了一個額外， – sromit

@sromit好的，不用逗號試試 - 看更新 –

與AWK查找和替換

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