獲取上個月的記錄

Question

我需要獲取上個月的客戶ID，數量和訂單數量。

Paper::select('customer_id', DB::raw('SUM(price) as `sum`') 
    ,DB::raw('COUNT(*) as `orders_per_month`')) 
    ->where('created_at', '>=', Carbon::now()->startOfMonth()) 
    ->groupBy('customer_id')->get() 

我試了，但如果最後一個月的客戶有沒有訂單，也不會被選中

Answer 1

嘗試COALESCE：

DB::raw('COALESCE(COUNT(*), 0) as `orders_per_month`') 

此功能允許您定義的默認值時，否則它是NULL。

http://dev.mysql.com/doc/refman/5.7/en/comparison-operators.html#function_coalesce

UPDATE：

我認爲，如果你選擇哪個具有上個月訂單唯一的客戶，那麼你肯定不會得到這些客戶沒有訂單。

你可以實現你需要的東西像什麼：

mysql> select * from cu; 
+----+----------+ 
| id | name  | 
+----+----------+ 
| 1 | Google | 
| 2 | Yahoo | 
| 3 | Mirosoft | 
+----+----------+ 
3 rows in set (0.00 sec) 

mysql> select * from so; 
+----+-------------+---------------------+-------+ 
| id | customer_id | created_at   | price | 
+----+-------------+---------------------+-------+ 
| 1 |   1 | 2016-08-23 12:12:12 |  2 | 
| 2 |   1 | 2016-09-24 12:14:13 |  3 | 
| 3 |   2 | 2016-09-25 00:00:00 |  5 | 
| 4 |   2 | 2016-09-12 09:00:00 |  3 | 
+----+-------------+---------------------+-------+ 
4 rows in set (0.00 sec) 

mysql> select cu.id as customer_id, coalesce(sum(so.price),0) as total, coalesce(count(so.customer_id),0) as orders_per_month from cu left join so on (cu.id = so.customer_id) where so.created_at >= '2016-09-01 00:00:00' or so.created_at is null group by cu.id; 
+-------------+-------+------------------+ 
| customer_id | total | orders_per_month | 
+-------------+-------+------------------+ 
|   1 |  3 |    1 | 
|   2 |  8 |    2 | 
|   3 |  0 |    0 | 
+-------------+-------+------------------+ 
3 rows in set (0.00 sec) 

然而，得到的查詢將不會爲這種或那種方式非常有效，你必須掃描所有客戶，並加入讓那些沒有命令。獲得帶有訂單的客戶列表並單獨訂購可能會更快，並將其與UNION或通過應用程序代碼合併。

mysql> select customer_id, sum(total) as total, sum(orders_per_month) as orders_per_month from (select id as customer_id, 0 as total, 0 as orders_per_month from cu union all select customer_id, sum(so.price) as total, count(so.customer_id) as orders_per_month from so where created_at >= '2016-09-01 00:00:00'group by customer_id) agg group by customer_id; 
+-------------+-------+------------------+ 
| customer_id | total | orders_per_month | 
+-------------+-------+------------------+ 
|   1 |  3 |    1 | 
|   2 |  8 |    2 | 
|   3 |  0 |    0 | 
+-------------+-------+------------------+ 
3 rows in set (0.00 sec) 

Answer 2

試試這個

Paper::select('customer_id', DB::raw('SUM(price) as `sum`'), 
      DB::raw('COUNT(*) as `orders_per_month`') 
     ) 
    ->whereMonth('created_at', Carbon::now()->month) 
    ->whereYear('created_at', Carbon::now()->year) 
    ->groupBy('customer_id')->get()