我有一個vb6多線程應用程序工作,我想使用互斥鎖來保護數據。預期的行爲是,當一個線程試圖獲得對現有互斥鎖的鎖定時,當調用「WaitForSingleObject」函數時,該線程將阻塞,直到發出互斥信號。我所遇到的是整個應用程序凍結。互斥鎖使用多線程時凍結整個應用程序
要複製我的項目,請打開VB6並創建一個新的Active X EXE。使用默認名稱創建一個模塊。將此代碼放置在它:
Option Explicit
Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long
Sub Main()
' this hack is necessary to ensure that we only 'create' the application window once..
Dim hwnd As Long
hwnd = FindWindow(vbNullString, "Form1")
If hwnd = 0 Then
Dim f As Form1
Set f = New Form1
f.Show
Set f = Nothing
End If
End Sub
接下來,創建一個類,使用默認名稱和該代碼添加到它:
Option Explicit
Private Const INFINITE = -1&
Private Const STANDARD_RIGHTS_REQUIRED As Long = &HF0000
Private Const SYNCHRONIZE As Long = &H100000
Private Const MUTANT_QUERY_STATE As Long = &H1
Private Const MUTANT_ALL_ACCESS As Long = (STANDARD_RIGHTS_REQUIRED Or SYNCHRONIZE Or MUTANT_QUERY_STATE)
Private Declare Function WaitForSingleObject Lib "kernel32" (ByVal hHandle As Long, ByVal dwMilliseconds As Long) As Long
Private Declare Function CreateMutex Lib "kernel32" Alias "CreateMutexA" (lpMutexAttributes As Any, ByVal bInitialOwner As Long, ByVal lpName As String) As Long
Private Declare Function OpenMutex Lib "kernel32" Alias "OpenMutexA" (ByVal dwDesiredAccess As Long, ByVal bInheritHandle As Long, ByVal lpName As String) As Long
Private Declare Function CloseHandle Lib "kernel32" (ByVal hObject As Long) As Long
Private Declare Function ReleaseMutex Lib "kernel32" (ByVal hMutex As Long) As Long
Private Const MUTEX_NAME As String = "mymutex"
Private m_hCurrentMutex As Long
Public Sub Class_Terminate()
Call ReleaseIt
End Sub
Public Sub LockIt(success As String)
Dim hMutex As Long
MsgBox "Lockit t:" & App.ThreadID
hMutex = OpenMutex(STANDARD_RIGHTS_REQUIRED, 0, MUTEX_NAME)
If hMutex <> 0 Then
Form1.Caption = "waiting on mutex"
MsgBox "waiting t:" & App.ThreadID
Dim res As Long
Do
'MsgWaitForMultipleObjects
res = WaitForSingleObject(hMutex, INFINITE)
DoEvents
Loop While res = -1
m_hCurrentMutex = hMutex
Else
Form1.Caption = "creating mutex"
m_hCurrentMutex = CreateMutex(ByVal 0&, 1, MUTEX_NAME)
End If
Form1.Caption = success
MsgBox success
End Sub
Public Sub ReleaseIt()
If m_hCurrentMutex <> 0 Then
Call ReleaseMutex(m_hCurrentMutex)
Call CloseHandle(m_hCurrentMutex)
m_hCurrentMutex = 0
End If
End Sub
最後,在主窗體上添加4個命令按鈕和下面的代碼:
Option Explicit
Dim c(1) As Class1
'Lock
Private Sub Command1_Click()
If c(0) Is Nothing Then Set c(0) = CreateObject("Project1.Class1")
Call c(0).LockIt("Object0")
End Sub
Private Sub Command2_Click()
If c(1) Is Nothing Then Set c(1) = CreateObject("Project1.Class1")
Call c(1).LockIt("Object1")
End Sub
'Free
Private Sub Command3_Click()
If c(0) Is Nothing Then Set c(0) = CreateObject("Project1.Class1")
Call c(0).ReleaseIt
End Sub
Private Sub Command4_Click()
If c(1) Is Nothing Then Set c(1) = CreateObject("Project1.Class1")
Call c(1).ReleaseIt
End Sub
Private Sub Form_Unload(Cancel As Integer)
Set c(0) = Nothing
Set c(1) = Nothing
End
End Sub
前兩個命令按鈕鎖定它們各自的互斥鎖。第二兩免費。注意在互斥鎖被鎖定之前,顯示一個唯一的線程ID。這讓我相信只有線程應該阻塞,而不是凍結整個應用程序。
任何援助將不勝感激。謝謝。
編輯:我忘了提及一個非常重要的部分:在項目屬性部分,我已經設置爲創建'每個對象的線程',這與msghox App.ThreadID調用的結果驗證。
Ahh-我忘了提及一個非常重要的部分:在項目屬性部分,我已經設置爲創建'每個對象的線程',並且這通過msghox App.ThreadID調用的結果進行驗證。關於使用相同的互斥體名稱,這是必要的,因爲我有各種變量需要保護。在這個演示應用程序中,沒有任何內容實際上受到保護,但在應用程序中,我使用互斥體名稱作爲共享變量/內存的名稱,以便即使我使用了互斥體,也不會凍結另一個線程的互斥體 - 因此只要它是一個不同的互斥體即可。 – 2011-12-19 20:19:44
@AuthmanApatira你能解釋一下應用程序何時會阻塞(我沒有安裝VB6)。 – 2011-12-19 21:01:04
我會點擊第一個鎖按鈕,並且會通知我線程ID,等待,然後我傳入的字符串(object0)提醒我它已成功獲取互斥鎖。當我點擊第二個鎖按鈕時,它會向我發送一個不同的,唯一的線程ID,等待---然後遊戲結束。如果我將dowhile循環註釋掉,並且只留下waitforsingleobject行,它將返回-1(失敗)並立即繼續處理該函數。所以這些事件實際上並沒有幫助/做任何事情。我在想,因爲它的一個新的線程,也許它需要處理窗口消息,因此msgwait線,但iono – 2011-12-19 22:53:43